# PSU EE 360 - ee360_hw9_sol (1) (4 pages)

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# ee360_hw9_sol (1)

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## ee360_hw9_sol (1)

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Pages:
4
School:
Pennsylvania State University
Course:
Ee 360 - Communications Systems I

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1 sin A cos A sin 2 A sin x 2 sin c x x of the sinc function and the definition we may go onsinto x write sin c x sin 2 B 0 t cos 2 B 0 t x sin c 2B 0 t cos 2 B 0 t we may go on to write 2 B 0 t EE 360 Communication Systems I Fall 2017 sin 2 B t cos 2 B t 0 0 sin 4 B 0 t 9 Due 12 05PM Dec 7 2017 sin c 2B 0 t cos 2 B 0 t Homework t 2 B 0 4 B 0 t Collaboration policy You are allowed Howsin to discuss homework problems with your classmates c 4 B 4B 0 t0 tyour sin ever you must write up and submit own solutions representing your own work 2 4 B t Accordingly Eq collaboration 2 in 1 we0policy get Any violationusing of the will be handled seriously 2 t sin c 4B sin c 4B 0 t 0 t 1 p Reading assignment 6 1 6 2 6 3 6 4 6 5 2 2 Eq 2 in 1 we get Accordingly using 1 16B 0t sin c 4B 0 t p t is the which desired 2 2result except for the scaling factor E 2 3 3 6 1 points 16B t Problem 6 9 a d on page 257 in the textbook 0 Solution Problem which is 6 9 the desired result except for the scaling factor E The bandwidth Problem 6 9 B of a raised cosine pulse spectrum is 2B0 f1 where B0 1 2Tb and f1 B0 1 a Thus B B0 1 For a data rate of 56 kilobits per second B0 28 kHz The bandwidth a 0 25 B of a raised cosine pulse spectrum is 2B0 f1 where B0 1 2Tb and f1 B0 1 a B B 28B0kHz 1 25 kHzrate of 56 kilobits per second B0 28 kHz Thus 1 x For a35data b 0 5 a 0 25 BB 28 42 kHz 28kHz kHzxx1 5 1 25 35 kHz c 0 75 b 0 5 BB 28 1 75x 1 5 49 kHz 28xkHz 42 kHz d 1 0 c 0 75 BB 28 56 kHz 28xx21 75 49 kHz d 1 0 Problem B 6 10 28points x 2 56Problem kHz 3 3 2 5 6 10 on page 257 in the textbook The raised 6 10 cosine pulse bandwidth BT 2B0 f1 where B0 1 2Tb For this channel BT 75 kHz Solution Problem For the given bit duration B0 50 kHz Then f1The raised 2B0 cosine BT pulse bandwidth BT 2B0 f1 where B0 1 2Tb For this channel BT 75 kHz For the25given kHz bit duration B0 50 kHz Then f1 12B f01 B BTT 0 5 25 kHz 1 f1 BT 0 5 6 6 1 Bit rate 1 Tb kilobits s 6 4 2 0 1

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