Wright CHM 1220 - CHM 1220 SI_Exam 2 Review_Rev 2_ANSWERS (2 pages)

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CHM 1220 SI_Exam 2 Review_Rev 2_ANSWERS



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CHM 1220 SI_Exam 2 Review_Rev 2_ANSWERS

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School:
Wright State University
Course:
Chm 1220 - General Chemistry II

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Questions Comments Suggestions Email me at stevens 161 wright edu SI Activity Exam II Review ANSWERS CHM 1220 Multiple Choice 1 Consider the gas phase equilibrium system 2 H2O g 2 H2 g O2 g Given that the forward reaction is endothermic which of the following changes will decrease the amount of H2O adding more oxygen adding a solid phase catalyst decreasing the volume of the container increasing the temperature at constant pressure adding He gas 2 The combustion of ethane is represented by the equation 2 C2H6 g 7 O2 g 4 CO2 g 6 H2O l Which of the below statements is true The rate of consumption of ethane is seven times faster than the rate of consumption of oxygen The rate of formation of CO2 equals the rate of formation of water Water is formed at a rate equal to two thirds the rate of formation of CO2 The rate of consumption of oxygen equals the rate of consumption of water CO2 is formed twice as fast as ethane is consumed 3 The equilibrium constant for reaction 1 is K Which expression is the equilibrium constant for reaction 2 1 SO2 g O2 g SO3 g 2 2 SO3 g 2 SO2 g O2 g K 2 K 1 2 K 2 K K 2 4 The rate law of a reaction is rate k A 2 B What are the units of the rate constant M 1 s 1 M3 s 2 1 M 2 s 1 Ms M2 s 1 5 At 22 C Kp 0 070 for the equilibrium NH4HS s NH3 g H2S g A sample of solid NH4HS is placed in a closed vessel and allowed to equilibrate What is the equilibrium partial pressure atm of ammonia assuming that some solid NH4HS remains 0 26 0 26 0 0049 K p PNH3 PH2S 0 070 x 2 x 0 070 0 26 0 070 3 8 0 52 6 At elevated temperatures methylisonitrile CH3NC isomerizes to acetonitrile CH3CN according to the reaction CH3NC g CH3CN g The dependence of the rate constant on temperature is studied and the graph below is prepared from the results 6 6 The energy of activation of this reaction is kJ mol 166 1 66 10 5 E 1 ln k a ln A 4 42 10 7 R T 4 42 10 4 10 5 6 5 y2 y1 a 1 94 104 Slope E R x2 x1 0 00215 0 00195 Slope 20000 Ea 20000 R 166 kJ mol Problems 7 A proposed mechanism for the reaction Br2 g 2 NO g 2 NOBr g is found below Determine the rate law for the overall reaction Note that a proper rate law cannot depend on the concentration of an intermediate because intermediates are generally unstable and are present in low non measurable concentrations k1 NO g Br2 g NOBr2 g k 1 fast reversible NOBr2 g NO g k 2 NOBr g very slow 2



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