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UMass Amherst PHYSICS 132 - Lab 2 In Class Assignment

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Atreyi SahaPhysics 132-Section LLMondays 8:00 AMHasbrouck 212February 8, 2016In-Class Questions: Wave Nature of Light1. Calculate the slit width of a single slit by analyzing the diffraction pattern. List possible sources of error in your answer.lambda = (a) * (w/2L)(6.33*10^-7) = a *(0.0173)a= 3.66*10^-5 m or 0.0366 mmBecause lambda is a known value since the lambda associated with a Helium-Neon laser is 633 nm, the possible sources of error in this calculation come from errors in measuring w or L. For example, to measure w, we must measure from the center of one dark spot to the center of another dark spot. Errors in measuring this value by using the edge of the dark spots to calculate can skew the calculated value for a. 2. Wavelength calculation for double slit and diffraction gratinga) Use the interference pattern from the double slit to calculate the wavelength of the laser.Compare this with the given value.) Repeat the wavelength calculation using diffraction grating. Given lambda = 633 nmDouble slit calculations: theta = y / L = 0.001 m /0.52 m = 0.001923 d (sin theta) = m (lambda)[d (sin theta)] / m = lambda(0.00025)(0.001923) / 1 = 481 nmDiffraction Grating:sin theta = (0.04) / sqrt (4*0.082 + 0.0652)sin theta = 0.29[d (sin theta)] / m = lambdalambda = 5.5*10^-7 m = 550 nmb)Discuss the differences in the pattern on the screen when using the grating and a double slit. Which one makes more accurate measurement and why?The difference between the double slit and diffraction grating is 70 nm. The diffraction grating makes a more accurate measurement with a value of 550 nm which is very close to theestablished value of 633 nm. While the location of the bright spots was the same, diffraction grating enabled the location of the spots to be much more well-defined therefore leading to more accurate measurements of Y. This is why the lambda value for diffraction grating was closer to the established


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UMass Amherst PHYSICS 132 - Lab 2 In Class Assignment

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