Sound ExperimentPhysics 131Hasbrook 210December 17th 2015NSAbstract: In this experiment we did three different sound experiments to compare how sound waves traveled in different ways. We used an ultrasound machine so show the sound waves, we found the time it took sound waves to travel a distance and back and we also found the speed of sound by using an air column.Questions1. Sound waves are longitudinal. Longitudinal waves are able to transport through matter without permanently moving that matter. Transverse waves move in a perpendicular pattern from their starting source. Transverse waves and longitudinal waves are different because longitudinal waves done move after they are emitted, but transverse waves do. Wavelength is the distance between each wavelength and the frequency is how many of those waves pass by a single point in a certain amount of time. The faster they morethe higher the frequency gets. The formulas that are given that relate wavelength and frequency to the speed of a wave is v=fx. 2.a. Nodes are where a wave is at its minimum height and an anti-node is where a wave is at its maximum height.b. The conditions for resonance for a tube open at one end would be found by taking the length that was measured between the tube when we could hear a sound was .4m and we got a frequency of 352.3. When the length of the pipe is increased it will make the wavelengths increase and also the frequency will get smaller because it will have a lower pitch.4.5. a. If we were to measure the wavelengths wit h a frequency of 345Hz then it would be Λ 354= 1m. The 3450Hz frequency would be 3450 Λ =.1m and the 345000kHz frequency would be 345,000,000 Λ = 1e^-6m.b. I think that in our experiments the most accurate would be the 3450Hz frequency because we got values that were close to .1m. This would create the most accurate experiment with the least amount of errors.c. If we used a 40kHz instead it would give us a wavelength that is smaller, which would make the experiment easier. This would result in a number value very similar to the number we calculated.6.a. We calculate the wavelength from the equation Λ = 2(d1 −d2). The distance from the point a to pint d is 3.10m and the distance form point b to point d is 2.40m. This would make d1 equal to 3.1 and d2 equal to 2.4. Then you fill them into the equation and you get the result of a wavelengthequaling to 1.4m.b. The speed of sound is found by the formula v=f Λ. We found the value of Λ to be 1.4 and the frequency is 240Hz. When multiplied together they equal 336m/s7. The temperature we were given was 21degrees Celsius. When using the equation v=20.1√(T C +273). When we fill in the temperature as 21 we get a result of v=344.64. The average for the v we got for our experiments was 348.7. This givesus a percent error of 1.178%. This error is due to human error. We may have not heard the resonance sound at the correct height, or measured the distance of the echo properly. When experimenting with sound I feel that there is a large amount of human error because to hear sound the will always be some sort of reaction 8. The cliff would have a height of 150.9m. I found this because I found out that the height of the sound is found by 2040-340t and then I filled in 4.9t^2=2040-340t. and then I switched everything in the equation around so it would equal aero. After switching everything to equal zero you can use the quadratic formula. This will result in two answers (5.55s and -74.9). Obviously the second answer doesn’tapply because it is negative. This give you the value for t and you can find the height by 4.9(5.55)^2.9. Conclusion After conducting this experiment and analyzing the data, we can conclude that the speed of sound can be calculated in many different ways , some ways more accurate than others. According to our data the direct measurement using the echo machine was the most accurate. I feel that it was most accurate because it had the least amount of room for human