!! !!! !In the above graph we do not show the transmissions from B->C that follow after the timeout of F5, since those do not affect the throughput calculations. 2. Consider the use of 1000 bits frames on a 1 Mbps satellite link with a 270 msec propagation delay.. Find the maximum link utilization for a. Stop and Wait Flow Control b. Continuous Flow Control with window size 7 c. Continuous Flow Control with window size 127 !Solutions: a) In S&W ARQ, only one frame is transmitted per RTT Link Utilization = Tf/(Tf + 2Tp) = (103/106)/{ (103/106)+0.27(2)}= 0.002 b) For Continuous ARQ, We are transmitting SWS frames in one RTT, hence the link utilization is 7(0.002) = 0.014
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