Chem 121 1st Edition Lecture 17 Outline of Last Lecture I. Bond PolarityII. Polarity of Molecules Outline of Current Lecture I. Physical vs. Chemical PropertiesII. Balancing Chemical EquationsIII. Molar MassIV. Stoichiometric CalculationsCurrent Lecture- Physical Properties: Characteristics NOT involving a change of substance’s chemical identity- Chemical Properties: Characteristics involving a change of substance’s chemical identity- Chemical Equation: Representation in formulas showing the identities and quantities of substance involved in a chemical change- Balancing Chemical Equations (steps):o Write the unbalanced equationo Start with the most complex formula, set the coefficient as 1, balance elements bound in such compoundo Most complex formula: most # of atoms and most types of atomso Balance rest of the compounds by starting with the left-most element (H or metal) in Periodic Table, then free elementso Adjust coefficients to smallest whole-number ratioo Check numbers of atoms and make sure they are equalo Specify the states of matters-solid l-liquid g-gas aq-aqueous solution- Molar Mass: Unique Molar Mass (MM) for element/molecule, identify element and/or compounds- Conversion factor: 1 mole = MM grams (two unit)- Moles: Conversion factors: 1 mole = NA atoms/molecules/ionsThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.- There is NO direct path from atoms to mass!!- Stoichiometry: Recipe of chemical reactionso Simplest numerical relationship between different chemical entities in a balancedchemical equation or a
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