BCHM 3050 1st Edition Lecture 37 Outline of Last Lecture I. Stoichiometry of Respiratory Electron TransportII. Proton GradientsIII. Chemiosmotic TheoryIV. ATP SynthaseV. Binding Change Mechanism for ATP SynthesisVI. Glycerol-3-phosphate ShuttleVII. Aspartate-Malate ShuttleVIII. Reduced Nucleotides Are Not EnoughOutline of Current Lecture I. How much ATP is produced by the complete oxidation of a hexose?II. Maximum yield of ATP per molecule of glucoseIII. Production of ATP in liver versus muscle/brain cellsCurrent LectureI. How much ATP is produced by the complete oxidation of a hexose?a. 1 glucose:i. Substrate level phosphorylation = 2 ATP (glycolysis)ii. SLP = 2 ATP (TCA) à 2 pyruvatesiii. NADH = 10iv. FADH2 = 2 v. NADH = 8 (Complex I)vi. NADH = 2 (Complex 2)vii. FADHs = 2 (Complex 2)viii. # ATP = 10(2.5) + 2(1.5) + 4b. 1 pyruvate:i. 1 NADH (Acetyl CoA)ii. 3 NADH (TCA)iii. 1 FADH2iv. 1 ATP (SLP)v. # ATP = 4(2.5) + 1(1.5) + 1 = 12.5II. Maximum yield of ATP per molecule of glucosea. Some ATP energy is lost when getting pyruvate into mitochondriab. Varying range of ATP produced (around 25-29)c. Do not get exactly 30 ATP because the process is not fool proofThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.d. Some ATP lost as heate. Questions on the test which have to do with the theoretical valuesIII. Production of ATP in liver versus muscle/brain cellsa. Liver:i. NADH: 10 à Complex 1 [10 protons per NADH]ii. FADH2: 2 à Complex II [6 protons per FADH2]iii. 100 + 12 = 112 protonsiv. 112/4 = 28 ATPv. Theoretical yield: 28 + 4 = 32 ATPb. Muscle/Brain:i. NADH: 8 à Complex Iii. NADH: 2 à Complex IIIiii. FADH2: 2 à Complex IIiv. 8 x 10 = 80 protonsv. 2 x 6 = 12 protonsvi. 2 x 6 = 12 protonsvii. 80 + 12 + 12 = 104viii. 104/4/ = 26 ATPix. Theoretical yield: 26 + 4 = 30
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