Chem 113 1st Edition Lecture 30 Outline of Last Lecture I. Salts that Yield Neutral SolutionsII. Salts that Yield Acidic SolutionsIII. Salts that Yield Basic SolutionsIV. Predicting Acid-Base Properties of SaltsV. Relating Ka and Kb for a Conjugate Acid-Base PairOutline of Current Lecture VI. Predicting the Net Direction of ReactionsVII. Comparison of acid-base reactionsVIII. Leveling Effect in H2OCurrent LectureI. Predicting the Net Direction of Reactionsa. The net direction of an acid-base reaction depends on the relative strength of theacids and bases involvedb. A reaction will favor the formation of the weaker acid and basei. Stronger acid+stronger base weaker acid+weaker baseII. Comparison of acid-base reactionsa. How favored are the acid-base reactions?i. Strong acid+ strong base1. H3O+ + OH-2H2O2. K=1/Kw=1.0x1014ii. Strong acid+ weak base1. HCl + NH3NH4Cl2. K can be determined by finding the ΔG° of the reactionThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.III. Leveling Effect in H2Oa. In H2O the strongest acid is H3O+b. In H2O the strongest base is OH-c. Remember: for any conjugate pair, Ka+Kb=Kwd. If a solution has a lower pH than the other, it is the stronger
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