CHEM 122 11th Edition Lecture 22 Outline of Last LectureI. Chemical Equilibriuma. Dynamic equilibriumb. Mass action expressionII. Equilibrium Constant ExpressionsIII. Equilibrium LawIV. Calculating Equilibrium ConstantV. Coal GasificationOutline of Current Lecture I. Equilibruim Law Expressionsa. Concentration of partial pressuresb. Relating Kc∧Kpc. Reaction quotientII. Equilibruim CalcuationsCurrent LectureEquilibruim Law Expressions: Kp=Pconcentrations of productsPconcentrations of reactants-Kp: concentration in partial pressure-P: partial pressure of concentration ex.) [A]xA general equationrelating the ∂ pressure K∧the concentration K : These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best Used as a supplement to your own notes, not as a substitute.-Kp=Kc(RT )∆ n-Kp:concentration in partial pressure-Kc: Concentation expression-R : ideal gas constant (.0821 L atm/ mol K)-T : Temerature K-∆ n: change in mol (mole products-mole reactants)Reaction Quotients:- for finding the initial concentration we calculate the reaction quotient (Q)- Comparision of Q with the equilibrium constant (K) allows us to preduct the reaction direction of reaction. o Q=K: the reaction is at equilibriumo Q<K: the reaction proceeds to generate productso Q>K: the reaction proceeds to generate more reactantsEquilibruim Calculation:When given the initial concentrations we can use those to find the equilibrium concentrations.1. Create an ICE chart. Initial .01 M 0 M 0 MChange -x +x +xEquilibruim .01-x x x2. Fill in the intital molarity which is given.3. With the chemical equation given mulipy x by the moles of each reactant and product that isin a gaseous state. In this example the moles of each molecule is 1. The products and reactants have to be opposite signs. In this example the reactants are negative and the products are positive.4. Then add the initial concentration with the change 5. Plug it into the Equilibruim Expression equation: (x )(x).01−xKc in this example K is given to us as 10.6. By simple algebra the equation is then turned into a quadratic equation: x2+10 x−.1=07. To solve for x use the quadratic equation: x=−b ±√b2−4 ac2 a then solve for x8. When x is solved then plug it back into the ICE chart and that will give the equilibrium
View Full Document
Unlocking...