DOC PREVIEW
K-State CHM 210 - LR 09 - 22 - 2014 with answers

This preview shows page 1 out of 3 pages.

Save
View full document
Premium Document
Do you want full access? Go Premium and unlock all 3 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

LR 09 22 2014 1 Name the following species according to the rules of systematic naming SO2 N2O4 P2O5 NH3 HCl aq sulfur dioxide dinitrogen tetroxide diphosphorus pentoxide ammonia hydrochloric acie ClO4 perchlorate ion NH4 ammonium ion ClO hypochlorite ion H2SO4 sulfuric acid HBr hydrogen bromide 2 Name the following ionic compounds that contain polyatomic ions Na3PO4 Ca OH 2 K2CO3 Mg NO3 2 BaSO4 sodium phosphate calcium hydroxide potassium carbonate magnesium nitrate barium sulfate 3 What is the empirical formula for N2H4 NH2 H2O H2O C6H6 CH 4 Give the formula for dinitrogen pentoxide aluminum phosphate magnesium nitrite tetraphosphorus decoxide hydrobromic acid N2O5 AlPO4 Mg NO2 2 P4O10 HBr aq 5 What is the molecular mass of N2O5 2 N 2 14 01 amu 5 O 5 16 00 amu 6 28 02 amu 80 00 amu 108 0 amu What is the molar mass of PH3 1 mol P 30 97 g 3 mol H 3 1 008g 33 99 g mol 7 73 4 grams of Ca NO3 2 is how many moles 73 4 g Ca NO3 2 x 8 9 0 447 mol Ca NO3 2 What is the percent composition of Ca NO3 2 Molar mass of Ca NO3 2 164 1 g mol from 3 above Ca 40 08 g Ca 164 1 g Ca NO3 2 x 100 24 42 Ca N 28 02 g N 164 1 g Ca NO3 2 x 100 17 07 N O 96 00 g O 164 1 g Ca NO3 2 x 100 58 50 O 1 25 moles of Ba OH 2 is how many grams 1 25 mol Ba OH 2 10 1 mol Ca NO3 2 164 1g Ca NO3 2 x 171 3 g Ba OH 2 1 mol Ba OH 2 214 1 g Ba OH 2 How many oxygen atoms are in 85 4 grams of CaCO3 85 4 g CaCO3 x 1 mol CaCO3 x 6 022 x 1023 CaCO3 x 3 O atoms 1 54 x 1024 100 1gCaCO3 1 mol CaCO3 1 mol CaCO3 oxygen atoms 11 Vanilla is a common flavoring agent It is composed of 63 2 C 5 30 H and 31 6 O Its molar mass is 152 g mol What is the molecular formula of vanilla 63 2g C x 1 mol C 12 0 g C 5 26 mol C 1 97 2 67 x 3 8 5 30g H x 1 mol H 1 008 g H 5 26 mol H 1 97 2 67 x 3 8 31 6g O x 1 mol O 16 0 g O 1 97 mol O 1 97 1 00 x 3 3 Empirical formula Mass of empirical formula C8H8O3 152 g Mass of molecular formula as given 152 g Molar mass Empirical formula mass 152 g 1 15 2g The molecular formula is the same as the empirical formula C8H8O3 This is an example of an empirical formula calculation in which after dividing my the smallest number of moles the numbers are still not whole numbers To convert them to whole numbers they had to be multiplied by 3


View Full Document

K-State CHM 210 - LR 09 - 22 - 2014 with answers

Download LR 09 - 22 - 2014 with answers
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view LR 09 - 22 - 2014 with answers and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view LR 09 - 22 - 2014 with answers and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?