Problem 5Problem 6 (i) No, counter example: Let 2ny, and 1 sin( )nx n , for any 0n, we have n ny x. However, ny converges to 2 and nx diverges. (ii) No, counter example as above, nx diverges but ny converges to 2.Problem 7 Note: The solution for Problem 7 (ii) is inaccurate. Another way to discuss the convergence is as: 1sin1 1lim lim sin lim lim cos 11Lnn n n nna nn nn =>
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