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NIU CHEM 210 - Dilution
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CHEM 210 1nd Edition Lecture 13 Outline of Last Lecture I. Using Balanced Equations for Word ProblemsII. Limiting ReactantsOutline of Current Lecture III. Dilute SolutionsCurrent LectureDilution is used to lessen the concentration of a solution by adding more volume to it. The amount of the solution does not change, however the volume does. Adding dilutions to solutions, makes the color lighter and clearer each time. A dark color means the solution is veryconcentrated, whereas a lighter color, means there is a range of dilutions added to it. There is a chemical equation used to solve dilutions in chemistry.M1 V1 = M2 V2. This equation simply means that the initial molar value and the initial volume equal the final molar value and final volume.You rearrange the equation, depending on what it is you are solving for.For example, if you were solving for the final volume or V2, you divide both sides of the equation by M2 to get V2 by itself. M1 V1 / M2 = V2. Let’s do an example. If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, determine the new concentration of the solution.First we find what the problem is looking for, which in this case is the final concentration or M2.These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.Next we rearrange our equation to solve for M2M1 V1 / V2 = M2Finally, we plug in the values. Make sure the units are consistent. For this case, I will convert the 1.0 L into mL, to be constant with the initial volume in mL.(1.6 mol/L) (175 mL) / (1000 mL) = M2M2 = 0.28 mol / L or 0.28


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NIU CHEM 210 - Dilution

Type: Lecture Note
Pages: 2
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