GENE 412 1st Edition Lecture 10Outline of Last Lecture I. Assortative Mating SelectionII. ExamplesOutline of Current Lecture I. Disassortative Mating SelectionII. ExamplesIII. Adding Mixtures of two species into one populationCurrent LectureI. Disassortative Mating Selectiona. Definition- Unlike individuals for a specific locus mating b. Characteristicsi. More Heterozygotesii. Powerful one locus evolutionary forceiii. Maintains Diversityiv. Allelic Frequency Changesc. Reason for above characteristicsi. Double heterozygotes breaks down Hardy-Weinburg Equlibriumii. Involves many allelesd. Equation for determining frequency of heterozygotes in a population i. At equilibrium  all Aa; F(a) & F(A) = 0.5ii. For n alleles F(An)=1/nII. Examples of Disassortative Matinga. HLA Locusi. Very prominent in humans1. Shows most married couples chose opposite genotype for HLA Locus than their spouseii. Can change allelic frequency dramatically in one populationiii. P(a) = .251. AA X Aa, Aa X aa, AA X aa are the only possible parental mating patterns for Disassortative mating2. After one generation of only these mating studies showed P’(a) = .375These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.III. Mixing of two species in one populationa. European and African Honey Bee Matingi. European Honey Bee; f(A) = .8, f(B) = .6ii. African Honey Bee; f(A) = .2, f(B) = .4b. Migration effect in population i. Mixture of population coming togetherii. mAf = .8iii. meuro = .2c. Another equation used for determining Di. D = m(1-m)(p1-p2)*(k1-k2)ii. D can be positive or negative iii. D is the measure of recombination or mixing of the genomeiv. So for the information above about the African & European HoneyBee1. D = .8*.2*(.8-.2)*(.6-.4) =