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UT Knoxville BIOL 240 - Quiz - 6 with key

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Name_________________________________ Section number_____________________Biology 240, GeneticsQuiz – 5, week of Nov 9, 2014One point for each question. Total points = 10 + 5 bonus = 15 ptsQ 1. The lac operator:a) Can regulate the lac operon in trans.b) Regulates the lac operon in cis only.c) Is an enhancer.d) Has binding sites for the CAP-cAMP complex.Q 2. The repressor produced by IS allele______:a) Does not bind with the operator.b) Prevents CAP protein to bind with the CAP site.c) Cannot bind with lactose.d) Binds with RNA polymerase.Q 3. Which of the following statements is correct with respect to the lac operon? a) Level of cAMP increases in presence of glucose.b) Level of cAMP is negatively regulated by glucose.c) Lac promoter binds with cAMP.d) Glucose binds with cAMPQ 4. Lac operon would not be turned on if_____:a) cAMP level is low.b) High level of CAP protein is produced.c) Adenylyl cyclase is inhibited.d) Both a and c are correct.Q 5. In an operon_____,a) Each gene is controlled by its own promoter.b) Each gene is controlled by its own operator.c) All genes are regulated by a common operator and a common promoter.d) Each gene is regulated by its own repressor.Q 6. E. coli strain with I – O+ Z+/ F’ I+ Z- genotype:a) Produces Beta-galactosidase constitutively.b) Produces beta-galactosidase only in presence of lactose.c) Cannot produce beta-galactosidase even in presence of lactose.d) Cannot produce repressor protein.Q 7. If E. coli is grown in presence of glucose, which of the following results are expected?a) Glucose will be broken down into lactose and galactose. b) cAMP will be converted to ATP.c) cAMP level will rise.d) Adenylyl cyclase enzyme will be inhibited. Q 8. In E. coli cAMP_____a) Causes allosteric modification of CAP.b) Inhibits the lac operon.c) Binds with the repressor.d) Binds with glucose.Name_________________________________ Section number_____________________Q 9. In I+OCZ+/F’I-O+ E. colia) Lactose is needed to turn lac operon on.b) Lac operon is constitutively on.c) Lac operon will be on in presence of glucose.d) All (a-c) are true.Q 10. Beta-gal enzyme will be synthesized in E. coli if media containing_______a) Glucose is used.b) Glucose plus lactose is used.c) Glucose plus galactose is used.d) Lactose alone is used.Q 11. Which of the following actions would turn off lac operon in the OC mutants?a) Addition of lactose in the medium.b) Addition of glucose in the medium.c) Addition of an F’ plasmid carrying I+ allele.d) Activation of CAP protein.Q 12. Which of the following compounds is preferred by E. coli for growth?a) Glucose.b) Sucrose.c) Lactose.d) Ribose.Q 13. Beta-galactosidase breaks down lactose into______:a) Two glucose molecules.b) Two galactose molecules.c) One glucose and one galactose molecule.d) Two lactose molecules.Q 14. A mutation is called transition mutation when_____a) Cytosine is replaced by a thymine.b) Adenine is replaced by a guanine.c) Purines are replaced by pyrimidines and vice versa.d) Both a and b are correct.Q 15. In pea plants, round seed (R) allele is dominant to wrinkled seed (r) allele, and yellow flower (Y) allele is dominant to white flower (y) allele. These two pairs of alleles assort independently. If a doubly heterozygous plant is test-crossed , in the F1__________a) All progeny will have round seed and yellow flower.b) Four different phenotypes in 9:3:3:1 ratios will be found.c) Proportion of plants with round seed or yellow flower will be 50%.d) All progeny will have wrinkled seeds and white


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