PHY 107 1st Edition Lecture 6 Outline of Last Lecture I. Motion along a straight line (cont.)Outline of Current Lecture II. Free fall motion - “Round trip” free fallIII. Graphical integration in motion analysis (non-constant acceleration)Current LectureFree Fall Motion: - Constant acceleration of 9.8 m/s2 (g: gravitational acceleration)- If the y-axis points upwards, a = -g- Recall the equations for constant acceleration (a replaced with g) Eq. 1) v = v0 – gt Eq. 2) y = y0 + v0t - g t22 Eq. 3) v2 – v02 = – 2g(y – y0) “Round Trip” Free Fall:- Throwing something up in the air and letting it fall back down- Travels from point A to point B, temporarily stops, then drops back down to A - The following questions regarding this diagram can be answered with the 3 constant acceleration equations: When will it reach maximum height? o v0 – gt1 = 0 → t1 = v0g What is the maximum height?o ymax = v0t1 - ¿122 = v022 g These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute. ABYa = -g When will it fall back to the initial position?o 0 = v0t2 - ¿222 → t2 = 2 v0g What is its velocity then? o v0 – gt2 = - v0 Graphical Integration in Motion Analysis (non-constant acceleration):- Must use integration to determine velocity (v(t)) and the position (x(t)) at any given time- Analytically: a = dvdt → dv = adt → ∫t0t1dv = ∫t0t1adt → v1 – v0 = ∫t0t1adt- Graphically: Change in velocity = ∫t0t1adt = [area under the a vs t curve between t0 and
View Full Document
Unlocking...