CHEM 210 1nd Edition Lecture 10 Outline of Last Lecture I. Naming CompoundsII. Brief Introduction to Stoichiometry A. The MoleOutline of Current LectureIII. Converting Using Moles Current LectureThe mole as mentioned previously, is simply 6.022 X 10^23 items. It does not change and one can convert between moles, molecules and atoms. For example, to get from molecules to grams, you multiply using the mole number (6.022 X 10^23).1 molecule H2O X (1 mol) / (6.022 X 10^23) X (18 H2O) / (1 mol) = 3 X 10^ -23 grams.To convert from molecules of H2O to grams, you have to multiply by the mole ratio in order to cancel out the amount of molecules. Then you multiply by the number of grams in H2O and divide by 1 mole since there are 18 grams in H2O in one mole. This will cancel out the moles and your answer will be left in grams.The Formula for glucose is C6H1206.Atoms/ molecules of the compound = 6 atoms C, 12 atoms H, 6 atoms O. You simply look at how many of each element there are in the compound. This represents the number of atoms ofeach element in the compoundMoles = 6 moles C, 12 moles H, 6 moles O.These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.Atoms/ moles of the compound (atoms per mole) = 6(6.022 X 10^23) C, 12(6.022 X 10^23) H, and 6(6.022 X 10 ^ 23) O. To calculate the atoms per mole, you multiply the amount of atoms tothe mole constant.Mass per molecule = 6(12.01 amu) C = 72.06 amu; 12(1.008 amu) H = 12.10 amu and 6(16.00 amu) O = 96.00 amu. To find the mass per molecule, you multiply the number of molecules to the atomic mass of the element. (This can be found using the periodic table)Mass per mole of a compound = 72.006 g C, 12.10 g H, 96.00 g O. You find the mass per molecule (previous step) and add grams to it. The equations to convert from different units;If you have the number of moles and you want to find grams, you multiply the number of molesby the number of grams in the compound, over 1 mol. The moles will cancel and you will be leftwith grams.# of moles X (mass in grams) / (1 mole) = gramsIf you start off with grams and you want to convert to moles, you multiply the number of grams to 1 mole and then divide by the number of grams in compound. The grams will cancel out and you will be left with moles.Mass in grams X (1 mole) / (number of grams) = molesIf you start off with moles and you want to convert to entities, you multiply the number of moles by 6.022 X 10^23 and divide by 1 mole which will cancel out the moles.# of moles X (6.022 X 10^23 entities) / (1 mole) = entitiesVice versa, if you want to convert from entities to moles, you multiply the number of entities by 1 mole and divide by 6.022 X 10^23 entities to be left with moles.# of entities X (1 mole) / (6.022 X 10^23 entities) =