Exam 1 Study Guide

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Exam 1 Study Guide

This is the study guide for the first midterm. It covers chapters 18-20 in the text book.


Pages:
5
Type:
Study Guide
School:
The University of Vermont
Course:
Phys 012 - Elementary Physics
Edition:
1
Documents in this Packet

Unformatted text preview:

Exam # 1 Study Guide Lectures: 1 - 8 Lecture 1 (January 12) What are the three types of charge transfer? Briefly describe each. 1. By friction: transfer of electrons between the two objects that are rubbed together 2. By conduction: transfer of charge without contact through polarization 3. By induction: transfer of charge by contact Lecture 2 (January 14) What is the net force on q1 in the diagram below? If q1 has a mass of 1.5 grams and it was free to move, what would be its acceleration? Fnet,x = F2,x + F3,x = [(k|+8μC||-5μC|)/(1.32)] + [(k|+8μC||+5μC|)/(1.32)] * cos (23°) = 0 Fnet,y = F2,x + F3,x = [(k|+8μC||-5μC|)/(1.32)] + [(k|+8μC||+5μC|)/(1.32)] * sin (23°) = 1.663x10-3 N Fnet = Fnet,y = 1.663x10-3 N Lecture 3 (January 16) Find the direction and magnitude of the net electric field at the origin in the diagram below. E1 = (k|+6μC|)/(0.04m)2 * cos(0°) = E2 = (k|+6μC|)/(0.04m)2 * cos(180°) = E3 = (k|+3μC|)/(0.05m) 2 * sin(90°) = E4 = (k|-8μC|)/(0.07m) 2 * sin(90°) = Enet,x = E1 + E2 = 0 Physics 012 1st Edition Enet,y = E3 + E4 = Electric field is pointed along the y-axis. Lecture 4 (January 21) With q2 present, the electric field at P is twice what it is when only q1 is present. Given that q1 = +0.50μC, find q2 when it is a) positive and b) negative. a) Eq2 = Eq1 (k|q2||P|)/4d2 = (k|q1||P|)/d2 4q1 = q2 q2 = +2.00 μC b) Eq2 = -3Eq1 (k|q2||P|)/4d2 = -3(k|q1||P|)/d2 -12q1 = q2 q2 = -6.00 μC Lecture 5 (January 23) A long, thin wire of length L has a positive charge Q distributed uniformly along it. Use Gauss’ law to show that the electric field created by this wire at a radial distance r has a magnitude of E = λ/(2πε0r). λ = Q/L (charge density) For a cylinder, A = 2πr2 + 2πrL Φ at top and bottom of cylinder (cos(90°) = 0). Only area on sides (2πrL) matters for this problem. Φ = EA E(2 πrL) = q/ε0 = λL/ε0 E = λL/2 πrLε0 = λ/(2πε0r) Lecture 6 (January 26)



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