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UVM PHYS 012 - Electric Fields
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Physics 012 1st Edition Lecture 3 Outline of Last Lecture II. Insulators: contain no free electrons that can move around easilya. Conduct electric charge poorlyIII. Coulomb’s Law: the magnitude F of te electrostatic force exerted by one point charge q1 on another point charge q2 is directly proportional to the magnitudes |q1| and |q2| of the charges and inversely proportional to the square of the distance r between them (Cutnell 535)a. F = (k |q1||q2|)/r2b. k = proportionality constant = 8.99 x 109 (N*m2)/C2F12 = - F21 (Newton’s 3rd Law)Σ F = ma, same mass = same a, just in different Directions (Newton’s 2nd Law)Problem: Where can a 3rd charge (q0) be placed so Fnet on it is zero?These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.Outline of Current Lecture IV. Review Problems:V. Electric Fieldsa. E = F/q0 in N/Cb. Electric field points toward negative charges and away from positive


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UVM PHYS 012 - Electric Fields

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