PHYS 115 1st Edition Lecture 3 Outline of Last Lecture I. DensityII. PressureOutline of Current Lecture III. Ideal FluidsIV. Continuity equationV. Bernoulli’s equationCurrent Lecture- Properties of an ideal fluido incompressible (i.e., density is constant)o flow is steady (i.e., flow is laminar not turbulent)o nonviscous (i.e., the fluid has no resistance to flow)- Volume flow rate Q (aka “flux”): the rate at which a volume of fluid flows through a tubeo- Equation of Continuityo- CR 1o Water flows through a pipe. At point 1, the pipe has a radius r. At point 2, the pipe has a radius r/2. How does the speed of the water at point 2 compare to thespeed of the water at point 1?o The volume is 4x at point 1.oA=π r2 ; A2=π (12r )2; A2=14π r2o Volume flow rate has to be equal, so the volume must be 4x at point 2- CR 2o Which of the following is a correct expression for the equation of continuity?o A1v1 = (v)(A + A + A)- CR 3o Which of the following is a correct expression for the sum of the cross-sectional areas of tubes 2, 3, and 4 (Atot)?These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.o Atot = (A1v1)/(v)- CR 4o The aorta has a cross-sectional area of 3.0 cm2. Blood moves through the aorta at approximately 30 cm/s. A capillary has a cross-sectional area of 2.8 x 10-7 cm2. Blood moves through a capillary at approximately 0.05 cm/s.o The aorta’s cross-sectional area must be greater than the sum of all the cross-sectional areas of all the capillaries in the body.o Use the equation of continuity.o The speed of the capillaries is slower than the aorta, so the cross sectional area must be greater to keep the two volume flow rates
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