PHYS 0175 1st Edition Lecture8Outline of Last Lecture II. FluxIII. Flux of Velocity FieldIV. Flux of Electric FieldV. Relation Between Electric Flux and ChargeVI. Gauss’ IdeaVII. Gauss’ law VIII.Sign of electric fluxOutline of Current Lecture IX. Total electric flux of boxX. Main use for Gauss’ LawXI. Linear Superposition of electric fields and applying gauss’ lawCurrent LectureII. Total electric flux of boxa. Sum up the surfacesb. Do not necessarily cancel outc. Electric field may depend on not just a constant, but a variabled. Must do top, bottom, left, right, front and rear surfaces and add upe. Dot product i*dot*i=1 i*j=0 i*k=0 i. Only parallel components matterii. Must have coordinate axisiii. Can take out electric field values only if those values are independent of the integral variableiv. If component contains a constant-will cancel out and be equal andopposite1. If not contains constant-not necessarily2. Check units at enda. Must be in N/C*mIII. Main use for Gauss’ Lawa. Electric field at a distance from sourcei. Main purposeii. However, this application is useless unless you can separate the electric field out of the integral by having one that isindependent of the integral variable1. Otherwise cannot solve the electric field with gauss’ lawb. Electric flux through any regular surfacei. Not the main use, flux is not as important in finding as electric fieldIV. Linear Superposition of electric fields and applying gauss’ lawa. If two charges and need to find electric field from a point between the twob. Cannot use only on Gaussian enclosed surface, because the electric field will not be uniformc. Must make two spheres, treat them separatelyd. Center around each one, passing the point of the observere. Solve for electric field separately and the net is the sum of the two fieldsf. If multiply dimensions, consider adding the components i. And find the resultant in direction r-hatii. Sphere is most
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