CHEM 2211 1nd Edition Lecture 30Outline of Last Lecture I. Benzyl and allylic halides Outline of Current Lecture I. E2 reactions Current LectureE2 Reactions: - Stands for Elimination reaction that is bimolecular. o Bimolecular: it involves two molecules in the transition state. The rate law for and E2 reaction: Rate= k [alkyl halides][base]- The rate of the reaction depends linearly on both the concentrations of the alkyl halide and the baseThis tells us both the alkyl halide and the base are involved in the transition state of the rate determining step. - This indicates that an E2 reaction is a one step reaction Mechanism for an E2 reaction: HO-H CH3 CH3CH2 – C – CH3 CH2=C – CH3 + H2O + Br-BrThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.The arrows so the flow of electrons. O- grabs H and H+ electrons go to the bond between C and CH2, the last that kicks off Br giving the bonding electrons between Br and C to Br creating Br- . This all is one step that eliminates Br from the reaction. An E2 reaction can produce two products when the reactant has two points in which the base can pull from such as in: CH3CH=CH2CH3 + CH2O- CH3CH=CHCH3 + CH2=CHCH2CH3 + CH3OH + Br- BrMajor 80% minor 20% The two products are not created in equal quantities therefore E2 reactions are regioselective. The more substituted the product the more stable it is and the more of it is
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