TAMU PETE 662 - hw 2 sol f14 (10 pages)

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hw 2 sol f14



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hw 2 sol f14

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Pages:
10
School:
Texas A&M University
Course:
Pete 662 - Production Engineering
Production Engineering Documents

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PETE 662 HW 2 Solution Fall 2014 Question 1 The input parameters required are summarized in Table 1 Table 1 Input Values for all models Net pay ft h Reservoir Pressure psi pe Wellbore Pressure psi pwf Fluid viscosity cp Volume Factor B0 Drainage length ft Drainage width ft Wellbore length ft L Wellbore Radius ft rw Horizontal Permeability md kH Vertical Permeability md kV a 50 3000 1500 8 1 1 4000 3000 5000 0 25 2 1 Joshi Economides model can not be applied to a fully penetrated well as the model assumed an elliptical horizontal flow and elliptical horizontal flow can not exist at the end of the drainage region if the well extends to the end of drainage region b Furui et al model can be used as shown below Distance to the reservoir boundary yb 1500 ft see Fig 1 Fig 1 Furui et al Model geometry of horizontal well in reservoir The mean permeability k k y k z 1 1 0 md Skin s 0 assumed as there is no mention of any formation damage Page 1 of 10 PETE 662 HW 2 Solution Fall 2014 kL pe p wf q hI ani y b 141 2 Bo ln 1 224 s rw I ani 1 hI ani For Pwf 1500 psi q 1 5000 3000 1500 50 2 1500 141 2 8 1 1 ln 1 224 0 2 0 25 2 1 50 118 8 STB d Production rate for different bottomhole pressure s are calculated and shown in IPR curve below Fig 2 Fig 2 IPR curve for Furui et al model c Babu and Odeh model can be applied as shown below Table 2 Input Values for Babu and Odeh Model see Fig 3 Drainage length ft b Drainage width ft a Position in width direction ft x0 Position in Length direction ft y1 Position in Length direction ft y2 Position in height direction ft z0 Page 2 of 10 5000 3000 1500 0 5000 25 PETE 662 HW 2 Solution Fall 2014 Fig 3 Babu and Odeh Model of horizontal well in reservoir First we calculate the shape factor CH ln CH 6 28 2 a 1 x0 x0 z ln sin 0 I ani h 3 a a h a 0 5ln 1 088 I ani h 2 3000 3000 1 1500 1500 25 1 088 12 914 ln C H 6 28 ln sin 0 5 ln 2 50 3 3000 3000 50 2 50 Now since the well is fully penetrating the reservoir partial penetration skin factor sR 0 The



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