TAMU PETE 662 - 662_HW1_soln (17 pages)

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662_HW1_soln



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662_HW1_soln

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Pages:
17
School:
Texas A&M University
Course:
Pete 662 - Production Engineering
Production Engineering Documents

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PETE 662 Spring 2014 Problem 1 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Problem 2 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Homework 1 Vertical Well Performance 1 21 14 1 28 14 Problem 3 Table Given Data Parameter Calculate Value Oil flow rate bbl day 500 WOR 1 5 Gas gravity 0 71 Oil gravity API 32 Reservoir Temperature F 150 GOR 500 Seperator Temperature F 100 Seperator Pressure psig 100 in terms of reservoir pressure P Calculate oil formation volume factor Calculate as a function of P PETE 662 Spring 2014 Plot Homework 1 Vertical Well Performance 1 21 14 1 28 14 as a function of P 1500 Liquid Flow rate bbl day 1450 1400 1350 1300 1250 0 500 1000 1500 2000 2500 Pressure psia 3000 3500 Matlab Code Qo 500 bbl oil day WOR 1 5 water oil ratio GOR 500 gas oil ratio gas gravity 0 71 gas gravity oil gravity 32 oil gravity in degrees API T 150 degrees Farenheit P 0 2 4336 A oil gravity T 460 Rs gas gravity P 1 187 56 06 10 10 393 A F T 60 oil gravity gas gravity Bo 1 4 67 10 4 Rs 0 11 10 4 F 0 1337 10 8 Rs F Ql Qo WOR Bo plot P Ql xlabel Pressure psia ylabel Liquid Flow rate bbl day 4000 4500 PETE 662 Spring 2014 Problem 4 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Homework 1 Vertical Well Performance 1 21 14 1 28 14 PETE 662 Spring 2014 Homework 1 Vertical Well Performance 1 21 14 1 28 14 Problem 5 Given Data Parameter re ft Pwf psi Gas gravity k Reservoir Temperature F h Pi psi Value 1490 3000 0 65 0 17 180 78 4613 We are told to assume the gas reservoir is under pseudosteady state and so we take to be Equation 4 47 can be rearranged into Equation 4 50 We can use the quadratic equation



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