Cameron KahnMuditha DiasExperiment 6 Post Lab2 April 2014Experiment 6: Design an Analysis: Choosing a SolventData: Linalool 54.1mgCarvone 51.3mgEugenol 66.4mgCinnamaldehyde68.6mgHexane 1Peak # Retention time (min)Area1 8.4 337816652 9.845 947023163 11.099 1298366214 12.216 146256402Hexane 2Peak # Retention time (min)Area1 11.092 28770972 12.209 3170599Hexane 3Peak # Retention time (min)Area1 11.092 21404792 12.208 2171796Hexane 4Peak # Retention time (min)Area1 3.561 16814682 9.84 3848233 11.092 11948714 12.209 925022Hexane 5Peak # Retention time (min)Area1 3.565 13382442 9.841 258383Standard sample Retention timeCompoundRetentiontime(min)Carvone 8.851Cinnamaldehyde 9.061Linalool 7.668Eugenol 9.7163 11.092 10280094 12.209 698198Diethyl 1Peak # Retention time (min)Area1 5.332 55163452 7.599 5134463 8.87 3314274 9.841 7039325 10.405 25272306 10.669 1848877 11.093 5315668 12.21 252097Diethyl 2Peak # Retention time (min)Area1 5.328 22126872 5.398 20534243 10.422 19975594 11.093 5193745 12.21 297530Diethyl 3Peak # Retention time (min)Area1 5.327 42051312 10.421 17187743 11.093 260326Diethyl 4Peak # Retention time (min)Area1 5.33 39154102 10.43 1598613Diethyl 5Peak # Retention time (min)Area1 5.33 35262382 10.438 1143825Ext. HexanePeak # Retention time (min)Area1 3.566 14900302 6.553 16919173 6.583 19879694 7.004 18767555 7.127 17637556 7.602 2843263327 7.883 40998948 8.858 1587962279 9.081 2053379Ext. DiethylPeak # Retention time (min)Area1 6.58 16599102 7.004 9019543 7.141 7428054 7.594 1776606215 7.887 19248506 8.853 927997637 10.419 2672162Standards Hexane as solvent Diethyl Ether as solventconcentration (x)Retention area (y)concentration (x)Retention area (y)linalool 0.006492 0.006492 no retention areaswere comparable to the standard sample retention table. If I had retention areas then I would be able to graph concentration versus area to get a linear function. From there I would have been able to solve for xwhich is the concentration of the analyte.0.00541 0.005410.004328 0.0043280.003246 0.0032460.002164 0.002164Carvone 0.006156 33781665 0.0061560.00513 0.005130.004104 0.0041040.003078 0.0030780.002052 0.002052Eugenol (1) 0.007968 94702316 0.007968 (2) 0.00664 0.00664 (3) 0.005312 0.005312 (4) 0.003984 384823 0.003984 (5) 0.002656 258383 0.002656Cinnamaldehyde0.008232 0.0082320.00686 0.006860.005488 0.0054880.004166 0.0041660.00274 0.00274****No graph could be created for Linalool or Cinnamaldehyde because retention areas were not comparable to the table of standard samples. No graphs could be created for the standards using diethyl ether as a solvent. If atleast 3 retention areas were given for the standards in each solvent then I would be able to create graphs that related the concentration (in ppm) versus retention area and fromthere found a line of regression to show the linear relationship. I could only graph Eugenol in Hexane.1. Compare the concentrations of the standard analytes vs. the extracted analytes for hexane (Remember you have 4 analytes) 0 0 0 0.01 0.01 0.01 0.01 0.01024681012f(x) = 0R² = 0Calibration curve for Eugenol in Hexaneconcentration (ppm)Peak Area Ext. HexanePeak # Retention time (min)Area1 3.566 14900302 6.553 16919173 6.583 19879694 7.004 18767555 7.127 17637556 7.602 2843263327 7.883 40998948 8.858 1587962279 9.081 2053379Closest retention area in the hexane extraction for Eugenol is 2053379. Plugging in that number in fory in the linear regression equation will yield x. X is our concentration of analyte in the hexane extraction. X=0.0031ppm. Comparing the 0.0031ppm concentration to Eugenol’s set of standard concentration2. Compare the concentrations of the standard analytes vs. the extracted analytes for diethylether (Remember you have 4 analytes)No graphs could be created due to lack of comparable retention areas for the standards therefore we could not compared any value to the diethyl extraction. If I had retention areas available, I would do the same steps as stated previously in question 1 where I would use the regression equation to solve for x and then compare that concentration with the set standard concentrations.3. Compare the extraction efficiency of each organic solvent for all analytes (Remember you still have 4 analytes) This is not practical because each group used different analytes and weighed different amounts of analyte to make their standard set of concentrations for each analyte. Getting each groups data would be a hard task to undergo.But lets say if everyone used the same analytes and the same masses one could perform a t-test comparing our extraction concentrations for each analyte to their extraction concentration for each analyte in the two solvents at the 95% confidence interval to see if the values are statistically differentor statistically the same. From there we could either accept or reject the null hypothesis. If the null hypothesis was rejected for the data not being significantly the same, one would have to accept the alternate hypothesis that would state the data was significantly different at the 95% confidence interval.The hardest part of the lab was not getting retention areas for each of the analyte.4. Make a recommendation regarding which solvent is “better” in this context and why (include numerical rationale). Looking at the class data, I would recommend hexane as the better solvent because it yielded more retention times for everyone than diethyl ether. To compare the solvents using numerical data one would need us to perform t-tests but we did not perform the t-tests to get numerical values to support my