PGCC CHM 103 - Problem Set on Tracking Reaction Progress (6 pages)

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Problem Set on Tracking Reaction Progress



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Problem Set on Tracking Reaction Progress

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Pages:
6
School:
Prince George’s Community College
Course:
Chm 103 - FURTHER EXPLORATIONS IN THE CHEMICAL WORLD

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CHM 103 Sinex Problem Set on Tracking Reaction Progress 1 Consider the titration of a weak acid HX as given below A weak acid sample of 216 1 mg was dissolved to make 15 00 mL solution This was titrated with 0 1050 M NaOH HX NaOH NaX H2O 14 50 45 40 10 35 8 30 25 6 20 derivative pH 12 15 4 10 2 5 0 0 0 5 10 15 20 volume of NaOH Locate the coordinates of the equivalence point Describe how you determined this Calculate the molar mass of the acid What is the acid dissociation constant Ka of the weak acid Explain or illustrate how you determined this What indicator would work for this titration Explain your choice Site the reference used 1 2 The table given below contains the conductometric titration data for the following precipitation reaction The AgNO3 is the titrant NaCl aq AgNO3 aq AgCl s NaNO3 aq Would this reaction show any visible signs If so what Plot the data and locate the equivalence point of the titration Explain and illustrate on the graph how you determined the equivalence point Volume mL 0 2 34 5 15 7 40 10 20 12 45 14 70 18 06 19 75 23 12 27 06 30 43 34 92 39 97 45 03 Conductivity 2898 2875 2864 2852 2845 2829 2806 2795 2783 2990 3519 3979 4577 5313 5957 Explain what ions are causing the conductivity at the following points initially before the equivalence point at the equivalence point after the equivalence point The ionic conductance at 25oC and infinite dilution for the Ag is 62 2 3 Consider the spectrophotometric titration of Cu NH3 4 2 with EDTA Here is the reaction occurring with EDTA as the titrant Cu NH3 4 2 dark blue EDTA 4 Cu EDTA 2 colorless v light blue 4NH3 colorless The titration is done at the max of Cu NH3 4 2 The Cu EDTA 2 complex has a very large formation constant Kf 1018 Plot the data in the table given below and locate the equivalence point Volume mL 0 3 0 6 0 9 0 12 15 18 21 24 Absorbance 0 505 0 411 0 297 0 209 0 107 0 051 0 049 0 050 0 048 Explain the cause of the absorbance for the titration at the following points initially



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