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1Chapter 11 Gases and Gas Exchange James Murray (4/27/01) Univ. Washington There are several reasons for studying gas exchange. Three important ones are: 1. The ocean is a sink for anthropogenic CO2 which is transferred to the ocean from the atmosphere by gas exchange. 2. Oxygen is a chemical tracer for photosynthesis. The gas exchange flux of O2 is an important flux in box models of the euphotic zone for calculating net biological production. 3. Gas exchange is the process by which O2 is transported into the ocean and is thus a control on aerobic respiration. I. Fundamental Properties of Gases The relative composition of the main gases in the atmosphere (ratio of one gas to another) is nearly constant horizontally and vertically to almost 95 km. Atmospheric water (H2O) is highly variable. Some trace gases involved in photochemical reactions can also be highly variable. A. Composition of the Atmosphere More than 95% of all gases except radon reside in the atmosphere. The atmosphere controls the oceans gas contents for all gases except radon, CO2 and H2O. Q. Can you explain why? Table 11-1 Gas Mole Fraction in Dry Air (fG) molar volume at STP (l mol-1 ) where fG = moles gas i/total moles N2 0.78080 22.391 O2 0.20952 22.385 Ar 9.34 x 10-3 22.386 CO2 3.3 x 10-4 22.296 Ne 1.82 x 10-5 22.421 He 5.24 x 10-6 22.436 (See also Table 6.2 in Libes) Some comments about units of gases: In Air In Water Pressure - Atmospheres Volume - liters gas at STP / kgsw 1 Atm = 760 mm Hg STP = standard temperature and pressure Partial Pressure of Gasi = P(i)/760 = 1 atm. 0°C Volume - liters gas / liters air Molar - moles / kgsw ppm = ml / l, etc Conversion: lgas/kgsw / lgas / mole = moles/kgsw (~22.4 l/mol) The pressure and volume units are the same at 760 mm Hg2Dalton's Law Gas concentrations are expressed in terms of pressures. Total Pressure = ΣPi = Dalton's Law of Partial Pressures PT = PN2 + PO2 + PH2O + ......... Dalton's Law implies ideal behavior -- i.e. all gases behave independently on one another (same idea as ideal liquid solutions with no electrostatic interactions). Gases are dilute enough that this is a good assumption. Variations in partial pressure (Pi) result from: 1) variations in PT (atmospheric pressure highs and lows) 2) variations in water vapor ( PH2O) We can express the partial pressure (Pi) of a specific gas on a dry air basis as follows: Pi = [ PT - h/100 Po ] fi where Pi = partial pressure of gas i PT = Total atmospheric pressure h = % relative humidity Po = vapor pressure of water at ambient T fi = mole fraction of gas in dry air (see table above) Example: Say we have a humidity of 80% today and the temperature is 15°C Vapor pressure of H2O at 15°C = Po = 12.75 (from reference books) Then, PH2O = 0.80 x 12.75 = 10.2 mm Hg If PT = 758.0 mm Hg PTDry = (758.0 - 10.2) mm Hg = 747.8 mm Hg Then: fH2O = PH2O / PT = 10.2 / 758.0 = 0.013 So for these conditions H2O is 1.3% of the total gas in the atmosphere. That means that water has a higher concentration than Argon (Ar). This is important because water is the most important greenhouse gas!3B. Solubility The exchange or chemical equilibrium of a gas between gaseous and liquid phases can be written as: A (g) ===== A (aq) At equilibrium we can define the familiar value K = [A(aq)] / [A(g)] Q At equilibrium does gas A stop moving between gas and liquid phases? No - only the net exchange is zero. There are two main ways to express solubility. 1. Henry's Law: We can express the gas concentration in terms of partial pressure using the ideal gas law: PV = nRT so that the number of moles n divided by the volume is equal to [A(g)] n/V = [A(g)] = PA / RT where PA is the partial pressure of A Then K = [A(aq)] / PA/RT or [A(aq)] = (K/RT) PA [A(aq)] = KH PA units for K are mol kg-1 atm-1; for PA are atm in mol kg-1 Henry's Law states that the solubility of a gas is proportional its overlying partial pressure. The table given below (from Broecker and Peng, 1982, p. 112) summarizes values of Henry's Law constants for different gases. Example (From Table 11-2): The value of KH for CO2 at 24°C is 29 x 10-3 moles kg-1 atm-1 or 2.9 x 10-2 or 10-1.53. The partial pressure of CO2 in the atmosphere is increasing every day but if we assume that at some time in the recent past it was 350 ppm that is equal to 10-3.456 atm. The concentration of CO2 in water in equilibrium with that partial pressure is [CO2(aq)] = KH PA = 10-1.53 x 10-3.456 = 10-4.986 mol/l Example (Solubility at 0°C)(see also Table 11-3): Gas Pi KH (0°C , S = 35) Ci (0°C, S = 35; P = 760 mm Hg) (from page 1) (from Table 11-2) N2 0.7808 0.80 x 10-3 62.4 x 10-3 mol kg-1 O2 0.2095 1.69 x 10-3 35.4 x 10-3 Ar 0.0093 1.83 x 10-3 0.017 x 10-3 CO2 0.00033 63 x 10-3 0.021 x 10-34Table 11-2 Figure 11-152. Bunson Coefficients Since oceanographers frequently deal with gas concentrations not only in molar units but also in ml / l, we can also define [A(aq)] = α PA where α = 22,400 x KH (e.g., one mol of gas occupies 22,400 cm3 at STP) α is called the Bunsen solubility coefficient. Its units are cm3 mol-1. Appropriate values are summarized in the table below from Broecker and Peng (1982. p. 111) Summary of trends in solubility: 1. Type of gas: KH goes up as molecular weight goes up (note that CO2 is anomalous) Q. Why? 2. Temperature: solubility goes up as Temperature goes down Q. Can you explain why? 3. Salinity: solubility goes up as S goes down Q. Can you explain why? Causes of deviations from Equilibrium: Refer back to the graph of oxygen versus Temperature in ocean surface water (Lecture 9). Causes of deviation from saturation can be caused by: 1. nonconservative behavior (e.g. photosynthesis (+) or respiration (-) or denitrification (+)) 2. bubble or air injection (+) 3. subsurface mixing - possible supersaturation due to non linearity of KH or α vs. T. 4. change in atmospheric pressure - if this happens quickly, surface waters cannot respond quickly enough to reequilibrate. Table 11-36II. Rates of Gas Exchange There are many non-equilibrium situations for which we'd like to know


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UW OCEAN 400 - Lecture Notes

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