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MIT 2 810 - Machining processes

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Machining processes2.810 Fall 2007Professor Tim GutowskiOutlineBasic Machine Configuration1Basic Mechanics1Geometry1,3Production machining1,2,3,4,5Environmental IssuesReadingsKalpakjian Ch 21-27 (Ch 20-26, ed 4)“Simplified Time Estimation Bookletfor Basic Machining Operations”Design for Machining handoutSingle minute exchange of dies(SMED) handout“A Job Shop” handoutOutline Basic Machine Configuration1 Single point machining Turning, boring, trepanning, planing Multiple point machining Drilling, milling, reaming, sawing, broaching,grindingMachining processesHorizontal Slab milling Face milling End millingCutterArborArborSpindleSpindleEnd millShankTurningMilling* Source: Kalpakjian, “ Manufacturing Engineering and Technology”** GrindingGrindingwheelDGrainsWorkpiecevVHorizontal-spindle surface grinderMachine ToolsColumnBaseHeadTableSaddleKnee*SpindlespeedselectorFeedchangegearboxCompound rest andslides (swivels)ApronBedLead screwFeedrodHeadstockSpindleCross slideWay sCarriageCenterTailstock quillTailstockBasic LatheVertical-Spindle Mill** Source: Kalpakjian, “ Manufacturing Engineering and Technology”*OutlineBasic Mechanics1 Power, Forces Heat, Tool materials, Rate limits New Technology to reduce these effectsSee Video on Plastic DeformationBasic Machining MechanismApproximationus ~ H (Hardness) t0tcφShear planeShear angleToolVChipWorkpieceα+-Rakeangle)42(61 u4 2 d uu 80%) to(65 u uu energy specific volworkwork dtd(work) Power VFppfriction workplasticSS!"##$$#=+======%&•••H'(('()*Specific energy, uSHence we have the approximation;Power ≈ us X MRRMRR is the Material Removal Rate or d(Vol)/dtSince Power isP = F * Vand MRR can be written as,d(Vol)/dt = A * VWhere A is the cross-sectional area of the undeformed chip, we canget an estimate for the cutting force as,F ≈ us × ANote that this approximation is the cutting force in the cutting direction.Basic Machining MechanismCutting Force Directions in MillingFpFcnFcFcnFpFcFcnFcFpFcnFpFcFc ~ H × Ac(Tangential Cutting Force ~ Chip Cross-section × Hardness)Feed per Tooth and MRRf = feed per tooth (m)w = width of cut (m)v (m/s)W = rotational rate (rpm)Consider the workpiece moving into the cutter at rate “v”. The travel in time t’is v*t’. During the same time, the cutter would rotate W*t’ times and theworkpiece would see 4W*t’ cutter teeth. In general, a cutter may have “N”teeth, so the feed per tooth isf = v / NWThe material removal rate (MRR) is,MRR = v w dwhere “d” is the depth of the tool into the workpiece.Top view of face millingWith 4 tooth cutterSide viewEx) Face milling of Al Alloywdf =DvwN = 4 (number of teeth)D = 2” (cutter diameter)Let w = 1” (width of cut), d=0.1” (depth of cut)f = 0.007” (feed per tooth),vs = 2500 ft/min (surface speed; depends oncutting tool material; here, we must have acoated tool such as TiN or PCD)The rotational rate for the spindle isW = vs / pD = 4775 rpmNow, we can calculate vw, workpiece velocity,f = vw / N W => vw= 134 [in/min]Material removal rate, MRR = vw*w*d = 13.4 [in3/min]Power requirement, P = us*MRR = 5.36 [hp]Cutting force / tooth, F ~ us*d*f = 111 [lbf]us from Table 21.2 (20.2 ed 4); Note 1 [hp min/in3] = 3.96*105 [psi]Ex) Turning a stainless steel barfD=1”dToolRecommended feed = 0.006” (Table 23.4 (22.4))Recommended surface speed = 1000 ft/minW = 1000 ft/min = 3820 rpm p*1” * 1ft/12”Material removal rate, MRR = 0.1*0.006* (p*1* 3820) = 7.2 [in3/min]Power requirement, P = us*MRR = 1.9*7.2 = 13.7 [hp]Cutting force / tooth, F ~ us*d*f = (1.9*3.96*105)*(0.1*0.006) = 450 [lbf]us from Table 21.2 (20.2 ed 4); Note 1 [hp min/in3] = 3.96*105 [psi]Let d = 0.1”Temperature Rise in CuttingAdiabatic Temperature Rise:r cp DT = uSNote : uS ~ H, HardnessDTadiabatic > ½ Tmelt (Al & Steel)Interface Temperature:DT = 0.4 (H / r cp)(v f / a)0.33v = cutting speedf = feeda = thermal diffusivity of workpieceNote v f / a = Pe = convection/conductionTypical temperature distributionin the cutting zone* Source: Kalpakjian, and Schmidt 5th ed** Reference: N. Cook, “ Material Removal Processes”Cutting tool materials & process conditionsTemperature (°F )Hardness (HRA )HRCF eed (in/rev )C utting speed (ft/min)m/minYearMachining time (min)* Source: Kalpakjian, “ Manufacturing Engineering and Technology”C utting Speed (ft/min)Tool life (min)Limits to MRR in MachiningSpindle Power – for rigid, well supported partsCutting Force – may distort part, break delicatetoolsVibration and Chatter – lack of sufficient rigidity inthe machine, workpiece and cutting tool mayresult in self-excited vibrationHeat – heat build-up may produce “welding”, poorsurface finish, excessive work hardening; can bereduced with cutting fluidSee Video on Rate Limits In MachiningTypical Material Removal Rate10-410-310-210-11 10 102EBM1EDM1,2Grinding3MachiningCreep Feed2GrindingLASER3Chem. Milling2[cm3/sec]25A, 6um RMS1Rough millingof Al > 35hp1m X 1m areaNote: 1cm3/sec = 3.67 in3/min* References: 1. Advanced Methods of Machining, J.A.McGeough, Chapman and Hall, 1988 2. Manufacturing Engineering and Technology, S. Kalpakjian, Addison-Wesley, 1992 3. Laser Machining, G. Chryssolouris, Springer-Verlag, 1991High speed Machining and AssemblyHigh Speed Machined aluminum parts are replacing built-upparts made by forming and assembly (riveting) in theaerospace industry. The part below was machined on a 5-axisMakino (A77) at Boeing using a 8-15k rpm spindle speed, and afeed of 240 ipm vs 60 ipm conventional machining. This partreplaces a build up of 25 parts. A similar example exists for theF/A-18 bulkhead (Boeing, St. Louis) going from 90 pieces(sheetmetal build-up) to 1 piece. High speed machining is ableto cut walls to 0.020” (0.51mm) without distortion. Part can befixtured using “window frame” type fixture.MRR = f d * N W wOutlineGeometry1,3 Micro-geometry: tolerance, surface finish Macro-geometry: 5 axes, form tools vs. softwareMicro-geometryExcellent surface finish and dimensionprecision are possible.Compare machining tolerances with otherprocesses. See figure 23.14 (22.15) and 35.19 (35.22) ofKalpakjianCompare surface finish with other processes,and various applications. See figure 23.13 (22.14) and 35.20 (35.23) ofKalpakjianWhy is machining so good?Variation Vs Part SizeMacro-geometry Machine tool


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MIT 2 810 - Machining processes

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