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CMU 15441 Computer Networking - Lecture

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Lecture 5 TransmissionPhysical and Datalink Layers: 3 LecturesFrom Signals to PacketsToday’s LectureWhy Do We Care?ModulationAmplitude and Frequency ModulationThe Frequency DomainSignal = Sum of WavesSlide 10Transmission Channel ConsiderationsThe Nyquist LimitPast the Nyquist LimitCapacity of a Noisy ChannelExample: Modem RatesLimits to Speed and DistanceSupporting Multiple ChannelsTime Division MultiplexingBaseband versus Carrier ModulationAmplitude Carrier ModulationFrequency Division Multiplexing: Multiple ChannelsFrequency versus Time-division MultiplexingCopper WireLight Transmission in FiberRay PropagationFiber TypesGigabit Ethernet: Physical Layer ComparisonRegeneration and AmplificationWavelength Division MultiplexingWireless TechnologiesThings to RememberSlide 32Analog versus Digital EncodingWhy Do We Need Encoding?EncodingNon-Return to Zero (NRZ)Non-Return to Zero Inverted (NRZI)Ethernet Manchester Encoding4B/5B EncodingSlide 40Other Encodings1Lecture 5TransmissionPeter SteenkisteDepartments of Computer Science andElectrical and Computer EngineeringCarnegie Mellon University15-441 Networking, Spring 2008http://www.cs.cmu.edu/~dga/15-441/S082Physical and Datalink Layers:3 Lectures1. Physical layer.2. Datalink layer introduction, framing, error coding, switched networks.3. Broadcast-networks, home networking.ApplicationApplicationPresentationPresentationSessionSessionTransportTransportNetworkNetworkDatalinkDatalinkPhysicalPhysical3From Signals to PacketsAnalog Signal“Digital” SignalBit Stream0 0 1 0 1 1 1 0 0 0 1Packets0100010101011100101010101011101110000001111010101110101010101101011010111001Header/BodyHeader/BodyHeader/BodyReceiverSenderPacketTransmission4Today’s LectureModulation.Bandwidth limitations.Frequency spectrum and its use.Multiplexing.Media: Copper, Fiber, Optical, Wireless.Coding.Framing.5Why Do We Care?I am not an electrical engineer?Physical layer places constraints on what the hardware network infrastructure can deliver= reality checkNeed to understand impact of the physical layer on the higher protocol layers»Fiber fiber copper?»Why do we need wires at all?»Error characteristic and failure modes»Effects of distance6ModulationSender changes the nature of the signal in a way that the receiver can recognize.»Similar to radio: AM or FMDigital transmission: encodes the values 0 or 1 in the signal.»It is also possible to encode multi-valued symbolsAmplitude modulation: change the strength of the signal, typically between on and off.»Sender and receiver agree on a “rate”»On means 1, Off means 0Similar: frequency or phase modulation.Can also combine method modulation types.7Amplitude and FrequencyModulation0 0 1 1 0 0 1 1 0 0 0 1 1 1 0 0 0 1 1 0 0 0 1 1 1 00 1 1 0 1 1 0 0 0 18The Frequency DomainA (periodic) signal can be viewed as a sum of sine waves of different strengths.»Corresponds to energy at a certain frequencyEvery signal has an equivalent representation in the frequency domain.»What frequencies are present and what is their strength (energy)Again: Similar to radio and TV signals.TimeFrequencyAmplitude9Signal = Sum of Waves=+ 1.3 X+ 0.56 X+ 1.15 X10Why Do We Care?How much bandwidth can I get out of a specific wire (transmission medium)?What limits the physical size of the network?How can multiple hosts communicate over the same wire at the same time?How can I manage bandwidth on a transmission medium?How do the properties of copper, fiber, and wireless compare?11Transmission Channel ConsiderationsEvery medium supports transmission in a certain frequency range.»Outside this range, effects such as attenuation, .. degrade the signal too muchTransmission and receive hardware will try to maximize the useful bandwidth in this frequency band.»Tradeoffs between cost, distance, bit rateAs technology improves, these parameters change, even for the same wire.»Thanks to our EE friendsFrequencyGood BadSignal12The Nyquist LimitA noiseless channel of width H can at most transmit a binary signal at a rate 2 x H.»E.g. a 3000 Hz channel can transmit data at a rate of at most 6000 bits/second»Assumes binary amplitude encoding13Past the Nyquist LimitMore aggressive encoding can increase the channel bandwidth.»Example: modems–Same f requency - number of symbols per second–Symbols have more possible valuesEvery transmission medium supports transmission in a certain frequency range.»The channel bandwidth is determined by the transmission medium and the quality of the transmitter and receivers»Channel capacity increases over timepskPsk+ AM14Capacity of a Noisy ChannelCan’t add infinite symbols - you have to be able to tell them apart. This is where noise comes in.Shannon’s theorem: C = B x log2(1 + S/N)»C: maximum capacity (bps)»B: channel bandwidth (Hz)»S/N: signal to noise ratio of the channel–Often expressed in decibels (db) = 10 log(S/N)Example:»Local loop bandwidth: 3200 Hz»Typical S/N: 1000 (30db)»What is the upper limit on capacity?–Modems: Teleco internally converts to 56kbit/s digital signal, which sets a limit on B and the S/N.15Example: Modem Rates1001000100001000001975 1980 1985 1990 1995 2000YearModem rate16Limits to Speed and DistanceNoise: “random” energy is added to the signal.Attenuation: some of the energy in the signal leaks away.Dispersion: attenuation and propagation speed are frequency dependent.»Changes the shape of the signalEffects limit the data rate that a channel can sustain.»But affects different technologies in different waysEffects become worse with distance.»Tradeoff between data rate and distance17Supporting Multiple ChannelsMultiple channels can coexist if they transmit at a different frequency, or at a different time, or in a different part of the space.»Three dimensional space: frequency, space, timeSpace can be limited using wires or using transmit power of wireless transmitters.Frequency multiplexing means that different users use a different part of the spectrum.»Again, similar to radio: 95.5 versus 102.5 stationControlling time is a datalink protocol issue.»Media Access Control (MAC): who gets to send when?18Time Division MultiplexingDifferent users use the wire at different points in time.Aggregate bandwidth also requires more spectrum.FrequencyFrequency19Baseband versus Carrier


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CMU 15441 Computer Networking - Lecture

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