PHY 2049:Exam IIReview Session Exam II:Summer ‘08A different problemSlide 4Ch 27Slide 6Slide 7Slide 8Slide 9Slide 10Slide 11PHY 2049:Exam II•The material consists of Ch. 26-29–Current and resistance–Circuits, Kirchhoff’s rules, junctions, loops and branches–Field effects, right hand rule–Field from – different sources. Right hand rule 2.•Problems from the book and old exams.Review Session Exam II:Summer ‘08 •Open office hours are in the afternoon:•The formula sheets cannot include questions and answers. No derivations are allowed.A different problem•Electrons (mass m, charge −e) are accelerated from rest through a potential difference V and are then deflected by a magnetic field B that is perpendicular to their velocity. The radius of the resulting electron trajectory is:A. √(2eV/m)/ B B. B√(2eV) /m C. √(2mV/e)/BD. B√2mV /e E. none of theseCh 27•A 18.0 Ω resistor and a capacitor are connected in series and then a 13.0 V potential difference is suddenly applied across them. The potential difference across the capacitor rises to 7.00 V in 1.50 μs. What is the capacitance in μF?(1) 0.11 (2) 2.3 (3) 4.5 (4) 6.8 (5) 1.9•The voltage across an initially uncharged capacitor is V( t) = V0 ( 1 – exp [-t/ RC]) where V0 = 13 is the applied voltage. Rearranging yields; exp −1.5×10−6 / RC =1−V /V0 =0.462 . Taking the log of both sides and solving for C yields C = 0.11 μF.Figure shows five 5.00 Ω resistors. Find the equivalent resistance between points (a) F and H and (b) F and G. (Hint: For each pair of points, imagine that a battery is connected across the pair.) a: 2.5 b: 3.125•What is i? All V = 10 Volts and all R = 4 Ohms•What is i? All V = 10 Volts and all R = 4 Ohms?•What is j? What is k?jk•What is i? All V = 10 Volts and all R = 4 OhmsjkR = 4 Ω, V = 4 V, what is the current through R?R = 4 Ω, V = 4 V, what is the current through R?8 = 4I => I =
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