� Graphical Interpretation of Convolution I The convolution integral is ∞ g(t) ∗ u(t)= g(t − τ )u(τ ) dτ −∞ Plot g(t − τ ) as a function of τ ,for g(t) and t as shown. g(t) t g(t-τ)=? τtGraphical Interpretation of Convolution I Plot g(t − τ ) as a function of τ ,for g(t) and t as shown. g(t) t My confidence that I have the correct answer is: 1. 100% 2. 80% 3. 60% 4. 40% 5. 20% 6. 0%Graphical Interpretation of Convolution I The plot of g(t − τ ) is given by g(t-τ) τt My answer 1. Was completely correct 2. Was mostly correct, with one or two minor errors 3. Had many errors 4. Was completely incorrectGraphical Interpretation of Convolution II The signals g(t) and u(t) are as plotted below. Plot g(t − τ )u(τ ) as a function of τ . g(t) t u(t) t g(t-τ)u(τ)=? τtGraphical Interpretation of Convolution II Plot g(t − τ )u(τ ) as a function of τ ,for g(t) and u(t) as shown. g(t) t u(t) t My confidence that I have the correct answer is: 1. 100% 2. 80% 3. 60% 4. 40% 5. 20% 6. 0%Graphical Interpretation of Convolution II The plot of g(t − τ ) is given by g(t-τ)u(τ) τt My answer 1. Was completely correct 2. Was mostly correct, with one or two minor errors 3. Had many errors 4. Was completely
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