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CTTherm-1 A piece of Krell metal is cool to the touch, even after a blaster pistol has fired several shots at it. [One shot can vaporize a tiger.] Compared to water, Krell metal has a heat capacity which is very, very..A) small B) large C) about the sameAnswer: Krell metal has a very large heat capacity. Q = m c T. In the clip from the movie "Forbidden Planet", we saw a blaster pistol fired into a Krell metal door. The blaster delivers a large amount of heat Q to the door, but the metal remained cool to the touch (small T), so the specific heat c must be very large.CTTherm-2 I put a 100W water heater in my cup of water. 100W = 100 J/s = 24 cal/s. I have 240 grams of water in my cup. How long to raise the temperature of my water by 1oC?A) 1 s B) 10 s C) 100 s D) None of theseAnswer: 10 s. 240 grams of water requires 240 cal to raise its temperature by 1oC. (1 calper gram per oC). With of power of 24 cal/s, we will need 10 s to get 240 cal.CTTherm-3 An ice cube is placed in a cup containing some liquid water. The water and ice exchange energy with each other but not with the outside world. After the water and ice come to the same temperature, is it possible the ice could freeze the water rather than the water melt some of the ice? A) Yes, the ice could freeze the water.B) No, the water will always melt some of the ice. Answer: Yes, the ice could freeze the water. If the ice was very cold, well below freezing, say T = -200oC, then heat would flow from the liquid water to the cold ice cube. The heat required to raise the temperature of the ice cube up to the melting point could be greater than the heat which the liquid water could give up before freezing.liquid watericeCTTherm-4Data) cice = 0.50 cal/(g oC) , cwater = 1.00 cal/(g oC), csteam = 0.48 cal/(g oC), L(ice-water)= 80 cal/g , L(water-steam)=539 cal/gWhich requires the most energy?A) Raise the temperature of 1 gram of liquid water 50 oC.B) Melt 1 gram of ice at T=0 oC.C) Raise the temperature of 1 gram of ice from 73K to 273K .D) Vaporize 0.5 gram of water at T=100 oC.Answer: Vaporizing 0.5 g of water requires (539/2) = 268 cal. Heating water 50oC requires 50 cal (assuming it stays liquid). Melting a gram of ice requires 79.7 cal. Heatinga gram ice from 73K to 273K requires 100cal.CTTherm-5 I put a 100W water heater in my cup of water. 100W = 100 J/s = 24 cal/s. I have 240 grams of water in my cup. How long to raise the temperature of my water by 1oC?A) 1 s B) 10 s C) 100 s D) None of theseAnswer: 10 s. 240 grams of water requires 240 cal to raise its temperature by 1oC. (1 calper gram per oC). With of power of 24 cal/s, we will need 10 s to get 240 cal.CTTherm-6 Heat from your house's furnace reaches the rooms in your house primarily by... A) conduction B) convectionC) radiation D) None of these. Answer: convection. If your furnace is "forced air" then hot air is blown through the vents into the rooms. This is bulk movement of heated matter (the hot air is transported from the furnace to the rooms). If you have steam heat, either in-the-floor hot water pipesor radiators, then a pump is moving the hot water/steam from the furnace to the rooms. It is still bulk movement of hot matter, still convection.CTTherm-7 Here in Boulder, it is cold in the winter and warm in the summer. Why? Which explanation below is the most accurate?A) In the winter, there is less solar radiation per unit area of the ground.B) The Sun is further from the Earth in the winter.C) Because of climate patterns, it is more cloudy than average in the winter, therefore lesssolar radiation than average reaches the ground. D) Because the Sun is lower in the sky in the winter, the sunlight travels through more airbefore it reaches the ground and the air absorbs heat, leaving less heat reaching the ground.Answer: Pink: In the winter, there is less solar radiation per unit area of the ground. Because of the tilt of the Earth's axis, in the winter, Boulder is tilted away from the Sun, and each square meter of ground receives fewer Solar


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CU-Boulder PHYS 2010 - Questions

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