X2.8 205PHYS-205(8) (Kaldon-18454) Name ______________________________________________WMU - Spring 2001 Exam 2 - 100,000 points + 20,000 ¶ points Book Title __________________________________________05/24/2001•Rev.3State Any Assumptions You Need To Make – Show All Work – Circle Any Final AnswersUse Your Time Wisely – Work on What You Can – Be Sure to Write Down EquationsFeel Free to Ask Any Questions¶2a ¶2b ¶2c ¶2eGo CART / No-Go CART (35,000 points)1.) (a) “The Sunday, April 29, 2001 Firestone Firehawk 600 CART race atTexas Motor Speedway was canceled. On the 1.5-mile oval, driverssustained loads of up to 5½ Gs for 18 of the 22 seconds it took tocomplete a single lap. Twenty-one of the 25 drivers in the starting fieldreported disorientation as a result, and given the potential for a driver"grey out," or loss of consciousness, according to Dr. Steve Olvey, CARTDirector of Medical Affairs, the decision was made to cancel the event inthe best interests of driver safety.”Consider that at 235 mph (105 m/s), a race car going around one of the curves at Texas Motor Speedwayundergoes a centripetal acceleration of 5.50 gee’s. What is the radius r of this curve?(b) The banking of the curves is a maximum of 24°. For a car ( m = 1200 kg ) going around a 24° bankedturn without friction, what is the value of the normal force, FN ?(c) If there was no friction, what would be the “natural” speed of this banked curve? If you did not get ananswer to (a), use r = 255 m.Physics 205 / Exam 2 Spring 2001 Page 2(d) If the coefficients of friction between the tires and thepavement are 1.00 and 0.810, then what is the fastest speed, v,that the car could go around this 24° banked curve safelywithout slipping?(e) If we ignore wind resistance and the jerk of changing gears, what is the shortestdistance that one of these CART race cars can go from rest to 235 mph (105 m/s)?Physics 205 / Exam 2 Spring 2001 Page 3Same But Different. Always Different. (30,000 points)2.) ¶(a) A force FNCx=+155. does 1450 J of work going from x0 = 1.00 m to x = 3.00 m. What isthe magnitude of the force at x0 = 1.00 m ?¶(b) An object of mass m = 3.00 kg begins its motion at x0 = 3.00 m, v0 = 3.00 m/s, a0 = 3.00 m/s²and an initial jerk of j0 = 3.00 m/s³. Find the equation for the force, F, acting on thisobject, where the motion of the object is determined by the following equation:¶(c) Find the work done when rFN= 500.$$i + 6.00N j and the displacement is 3.33 m @ 270°. (d) Two wedge masses are stacked together as shown Draw the Free Body Diagrams for both wedgesand indicate whether Block 2 needs to be moving to the Left or the Right so that Block 1 does not slide.There is no friction in this problem. Note that m1 < m2 .¶(e) An object of mass 6.25 kg has a force that follows the following equations. Find the vector positionrs at time t = 1.00 sec. Assume all other constants are zero.Ft N Ns Nsx() . . / . /=+ +600 600 60022ttFt N Ns Nsy() . . / . /=+ +600 600 60022ttdxdtms444300= ./Physics 205 / Exam 2 Spring 2001 Page 4Dark Angel Rules (35,000 points)3.) Sarah is a bicycle messenger just like Max on Dark Angel. TodaySarah is riding up in an elevator (loaded mass = 877 kg) from the firstfloor to the top floor at 10.0 m/s for 46.0 seconds. (a) Find the tension Tof the elevator cable. Assume that the cables attaching to the elevatorare purely vertical.(b) Find the work needed to lift the loaded elevator at 10.0 m/s for 46.0 seconds.(c) Find the work that the motor needs to do on the cable to lift the loaded elevator at 10.0 m/s for 46.0seconds.(d) Find the power of the motor to do this work. Give answer first in Watts, then in horsepower (h.p.).(e) At the top floor, as Sarah gets off, a penny on the floor falls down the elevator shaft. What will be thepenny’s speed when it reaches the first