Using effective diameter: Table 6.4: 2θ=60 deg Î P0f=53.3Î Deff=64/53.3*Dh=1.2 Dh=0.5196 and ε/Deff=0.000289 ()224.542/fQgAQDLfhhf== 134)4.54()2.32)(00234.0(132=⇒=== fQfQQgQfhPowerfρ 1st iteration: Guess: f=0.02 Î Q=18.9 ft3/s Î251000)/(Re ==μρeffDAQ f=f(Re=251000, ε/Deff=0.000289)Î f=0.017207 2nd iteration: f=0.017207 Î Q=19.82 ft3/s Î263100)/(Re ==μρeffDAQ f=f(Re=263100, ε/Deff=0.000289)Î f=0.017122 3rd iteration: f=0.017122 Î Q=19.85 ft3/s Î263500)/(Re ==μρeffDAQ f=f(Re=263500, ε/Deff=0.000289)Î f=0.0171186 converged Î Q=19.855 ft3/s %3.16.196.19855.19)()()(=−=−hheffDQDQDQ Using effective diameter gives 1. 3% lager flow
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