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NIU PHYS 600 - Coulomb Scattering

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Coulomb ScatteringHyperbolic OrbitsReoriented ViewImpact ParameterRutherford Cross SectionLunar MissLunar FrameEnergy BoostCoulomb ScatteringCoulomb ScatteringHyperbolic OrbitsHyperbolic OrbitsThe trajectory from an The trajectory from an inverse square force inverse square force forms a conic section.forms a conic section.•ee < 1 ellipse < 1 ellipse•ee =1 parabola =1 parabola•ee >1 hyperbola. >1 hyperbola.The force center is at a The force center is at a focus.focus.attractive focusrcos1)1(2eearrepulsive focusa aeer1cos Reoriented ViewReoriented ViewOrient the incident axis to Orient the incident axis to horizontal. horizontal. Scattering mass forms a Scattering mass forms a hyperbolic trajectory.hyperbolic trajectory.attractive focusrrepulsive focusa aecot)2tan(2tan 111112tan22eeehmv0xb2221EJe 2222tanEJmImpact ParameterImpact ParameterThe potential is defined at The potential is defined at infinity.infinity.The impact parameter would The impact parameter would be closest approach for no be closest approach for no force.force.•Compare to angular Compare to angular momentummomentumbmvJ02021mvE hmv0xbrV2020212))((22tanbmvmvmbmv202tan2cot20mvb Rutherford Cross SectionRutherford Cross SectionScattering cross section is Scattering cross section is based on the potential.based on the potential.•Impact parameterImpact parameter•Differential impact Differential impact parameterparameterThe result is the Rutherford The result is the Rutherford scattering cross sectionscattering cross sectionbbdbd2dbd)2(sinsin22cot22020mvmvb )2(sin220dmvdbdmvd)2(sinsin224220Lunar MissLunar MissProblemProblemA spaceship of mass A spaceship of mass mm moving with velocity moving with velocity vv00 approaches the Moon.approaches the Moon.The impact parameter is The impact parameter is bb..The velocity The velocity vv00 is is perpendicular to the orbital perpendicular to the orbital velocity velocity VV of the moon. of the moon.xbmV0vfvShow that if the spaceship Show that if the spaceship passes behind the Moon it passes behind the Moon it gains kinetic energy as it gains kinetic energy as it leaves the Moon.leaves the Moon.MLunar FrameLunar FrameThe moon is much more The moon is much more massive.massive.•Lunar frame is CMLunar frame is CM•Incident and final energies Incident and final energies same in CMsame in CMGMbv2022cotcos1cos12cot2cot20mvGMmb 12sin2m1v0xbbMEnergy BoostEnergy BoostIn the Moon’s frame In the Moon’s frame the velocity the velocity components come components come from the scattering from the scattering angle.angle.In the observer’s In the observer’s frame the velocity is frame the velocity is boosted by the boosted by the moon.moon. sinˆcosˆ00vVjvivf 2200222021sinsin2cos vVvVvmKf sin2022021VvVvmKf


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NIU PHYS 600 - Coulomb Scattering

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