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EIU CIS 3200 - Network Management 1

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1Network Management 1School of BusinessEastern Illinois University © Abdou Illia, spring 2004(Week 15, Monday 4/19/2004)2Learning Objectives Generating Useful Statistics– Availability– Reliability Centralized Network Management3Generating Useful Statistics Statistics: Data about network operation or network devices operation Example: Availability of a modem, Reliability of a Hub, transmission speed, etc. Statistics are very helpful for network management– Could help identifying problems in Network operation– Could be used to demonstrate the need to invest in technologyQ: What kind of tools, already introduced in class, can be used to generate useful statistics?24Availability Availability: probability that a particular component or system will be available during a fixed time period Availability is function of:– Mean time between failures (Given by manufacturer or generated based on past performance)– Mean time to repair (Found in studies or in our archives) Mean time between failures (MTBF) is the average time a device or system will operate before it fails. Mean time to repair (MTTR) is the average time necessary to repair a failure5 Standard equation:A(t) = a/(a+b) + b/(a+b) x e-(a+b)tin which: a = 1/MTTRb = 1/MTBFe = natural log functiont = the time interval Approximation equation:Availability% = (Total available time – Downtime)/Total available timeAvailability6Suppose we want to calculate the availability of a modem that has a MTBF of 3000 hours and a MTTR of 1 hour. The availability of this modem for an 8-hour period is:a = 1/1b = 1/3000 = 0.00033A(8 hours) =1/(1 + 0.00033) + 0.00033/(1 + 0.00033) x e-(1 + 0.00033)8= 0.9997 + 0.00033 x 0.000335= 0.9997AvailabilityQ: What will be the availability of the modem if the Approximation equation is used?A(t) = a/(a+b) + b/(a+b) x e-(a+b)t37Availability A component has been operating continuously for three months. During that time, it has failed twice, resulting in downtime of 4.5 hours. Calculate the availability of the component during that three-month period using the Approximation method.8Availability To calculate the availability of a system of components:– Calculate the availability of each component– Find the product of all availabilities Example: If a network has tree devices with availabilities of 0.992, 0.894, and 0.999, the availability of the network is:0.992 x 0.894 x 0.999 = 0.8869Reliability Reliability: probability that a component or system will be operational for the duration of a transaction time t.  Reliability is function of:– Mean time between failures– Transaction time Mean time between failures (MTBF) is the average time a device or system will operate before it fails. Transaction time is the time interval of operation to complete a given transaction.410ReliabilityReliability is defined by the equation:R(t) = e-btin which: b = 1/MTBFt = the time interval of the operation11ReliabilityWhat is the reliability of a modem if the MTBF is 3000 hours and a transaction takes 20 minutes, or 1/3 of an hour (0.333 hours):R(t) = e-btb = 1/MTBF = 1/3000t = 0.333R(0.333 hours) = e -(1/3000)(0.333)= e -0.000111= 0.99989Q: If a component has a MTBF of 500 hours and a transaction takes 4 seconds, calculate the reliability of the component 12Summary QuestionsSee slides # 6, 7,


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EIU CIS 3200 - Network Management 1

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