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MSU CEM 142 - weak acids

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CEM142 1nd Edition Lecture 7Outline of Last Lecture I. Aqueous equilibriaII. ElectrolytesIII. Strong acids and basesOutline of Current Lecture II. Weak acids and basesIII. Percent ionizationCurrent Lecture-brief review from last lecture-H2O + H2O  H3O+ + OH--equilibrium heavily favors the left side (reactants)-Kw = [H3O+][OH-] = 10-14 for pure water at 25 degrees Celsius-pH = -log[H3O+]-acids-HA + H2O  A- + H3O+-an acid donates its H+ to water-example: HCl + H2O  Cl- + H3O+-bases-B + H2O  BH+ + OH--a base accepts H+ from water-example: NH3 + H2O  NH4+ + OH-These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.-strong acids and bases: they are completely dissociated; equilibrium is pushed 100 percent to the right-weak acids and bases: they are partially dissociated; equilibrium is not pushed 100 percent to the right-percent ionization-% ionization = [A-]/total concentration x 100-the more you dilute a solution, the percent ionization will


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MSU CEM 142 - weak acids

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