Guy, Good – Homework 5 – Due: Mar 8 2004, 1:00 pm – Inst: Jon Valvano 1This print-out should have 15 questions.Multiple-choice questions may continue onthe next column or page – find all choicesbefore making your selection. The due time isCentral time.EE345L Valvano Homework 5.001 (part 1 of 1) 10 pointsA four-step output sequence repeated overand over will cause a stepper motor to spin.Which output sequence will rotate a step-per motor?1. None of these choices is correct.2. 1,2,4,8,1,2,4,8,...3. 0,1,2,3,0,1,2,3,...4. 1,2,3,4,1,2,3,4,...5. 9,10,6,5,9,10,6,5,...002 (part 1 of 1) 10 pointsAssume a stepper motor has 200 steps/rot,and the software outputs a new commandevery 21 ms/step.Assuming the motor has not stalled, whatis the rotational speed of this stepper? Giveyour answer in rpm.Answer in units of rpm.003 (part 1 of 3) 10 pointsThe following figure shows Moore finite statemachine. There are three states named S1 S2S3. There is one input signal, connected toPH0, which can be high or low. There is an8-bit output, connected to PORTJ.S121S237S345010101The following program is supposed to im-plement this Moore finite state machine.const struct State{xxx Out;const struct State *Next[2];};typedef const struct State StateType;#define S1 &FSM[0]#define S2 &FSM[1]#define S3 &FSM[2]StateType FSM[3]={{21,{S2,S3}},{37,{yyy}},{45,{S1,S2}}};void main(void){char Input;StatePtr Pt;DDRH = 0;DDRJ = 0xFF;Pt = S1;for(;;){PORTJ = Pt->Out;Input = PORTH&0x01;Pt = Pt->Next[Input];}}What C code should be placed in the xxxposition?1. None of these choices is correct.2. volatile.3. short.4. static.5. char.6. const.004 (part 2 of 3) 10 pointsWhat value should be placed in the yyy posi-tion?1. S1,S2.2. S1,S3.Guy, Good – Homework 5 – Due: Mar 8 2004, 1:00 pm – Inst: Jon Valvano 23. None of these choices is correct.4. S3,S1.5. S2,S3.6. 37.005 (part 3 of 3) 10 pointsAfter running for a while with a constantinput value of 1, what pattern of outputs willoccur?1. 21.2. 45.3. 45,37,21,45,37,21,....4. None of these choices is correct.5. 21,37,45,21,37,45,....6. 37.006 (part 1 of 4) 10 pointsThe following figure shows Mealy finite statemachine. There are three states named S1 S2S3. There is one input signal, connected toPJ0, which can be high or low. There is a16-bit time for each state, which contains thetime to wait in microseconds. There is a 1-bitoutput, connected to PH0.S120µsS250µsS310µs0/11/00/01/10/01/0The following program is supposed to im-plement this Mealy finite state machine. No-tice the sequence of actions performed by thiscontroller is 1)wait, 2) read input, 3) performoutput, and 4) go to next state. You may as-sume the Wait function delays for the num-ber of 125ns cycles as specified in the inputparameter.const struct State{xxx Time;char Out[2];const struct State *Next[2];};typedef const struct State StateType;#define S1 &FSM[0]#define S2 &FSM[1]#define S3 &FSM[2]StateType FSM[3]={{160,{1,0},{S2,S3}},{400,{yyy},{S3,S1}},{80, {0,0},{S1,S2}}};void main(void){char Input;StatePtr Pt;DDRH = DDRH|0x01;DDRJ = DDRJ&0xFE;Pt = S1;for(;;){Wait(Pt->Time);Input = PORTJ&0x01;zzzPt = Pt->Next[Input];}}What code should be placed in the xxxposition?1. static.2. char.3. long.4. short.5. volatile.007 (part 2 of 4) 10 pointsWhat value should be placed in the yyy posi-tion?1. S2,S3.2. S1,S2.Guy, Good -- Homework 5 -- Due: Mar 8 2004, 1:00 pm -- Inst: Jon Valvano 33. 0,1.4. 0,0.5. 1,0.008 (part 3 of 4) 10 pointsWhat code should be placed in the zzz posi-tion?1.PORTJ = Pt->Out;2.PORTH = Pt->Out[Input];3.PORTH = Input;4.PORTH = Out[Input];5.PORTH = Pt->Out;6.PORTH = PORTJ;009 (part 4 of 4) 10 pointsAfter running for a while with a constantinput value of 0, what pattern of outputs willoccur?1. A constant low.2. Can not be determined from this infor-mation.3. A constant high.4. A repeating pattern of an output high for50 us, followed by an output low for 30 us.5. A repeating pattern of an output high for20 us, followed by an output low for 60 us.010 (part 1 of 1) 10 pointsWhat is the difference between a Mealyfinite state machine and a Moore finite statemachine?1. The outputs of a Mealy finite state ma-chine depend just on the state, while the out-puts of a Moore finite state machine dependon both the state and the input.2. The outputs of a Moore finite state ma-chine depend just on the state, while the out-puts of a Mealy finite state machine dependon both the state and the input.3. The outputs of a Moore finite state ma-chine depend just on the state, while the out-puts of a Mealy finite state machine dependon just the the input.4. None of these choices is correct.5. A Moore finite state machine is moreefficient than a Mealy finite state machine.6. A Mealy finite state machine allows for atime delay in each state, while a Moore finitestate machine does not.011 (part 1 of 1) 10 pointsWhich address is the output compare 0 vec-tor?1. 0xFFF02. 0xFFEE3. 0xFFFE4. 0xFFE05. 0xFFFA6. none of the other answers is correct.012 (part 1 of 1) 10 pointsWhich interrupt number do you use whencompiling an output compare 7 ISR usingGuy, Good – Homework 5 – Due: Mar 8 2004, 1:00 pm – Inst: Jon Valvano 4Metrowerks? For example, what number goesinto the xx spot in the following C code?interrupt xx void handler(void){TC7 = TC7+20000;TFLG1 = 128;}013 (part 1 of 1) 10 pointsWhich software arms the output comparechannel 4 on the 812A4? For the 9S12C32,substitute TIE for TMSK1 and substituteTSCR1 for TSCR. If more than one soft-ware is possible, choose the friendly version.1.TSCR = 0x80;TIOS |= 0x10;TMSK1 &= 0xEF;2.TSCR = 0x80;TIOS = 0xFF;TMSK1 = 0xFF;3.TSCR = 0x80;TIOS |= 0x10;TMSK1 = 0x10;4.TSCR = 0x80;TIOS |= 0x10;TMSK1 |= 0x10;5.TSCR = 0x80;TIOS |= 0x10;TFLG1 |= 0x10;6.TSCR = 0x80;TIOS |= 0x10;TMSK1 = 0x00;014 (part 1 of 1) 10 pointsOn both the 812A4 and the 9S12C32, thetimer channel 7 flag, C7F, is bit 7 of theTFLG1 register. Assume the channel is con-figured as output compare. Which of thefollowing statements best describes the soft-ware action that will set the timer channel 7flag?1. The software reads the TCNT register.2. The software writes a 1 to the C7F bit.TFLG1 = 0x80;3. The software can not set C7F, but thisbit is set by the timer hardware when TC7matches TCNT.4. The software executes the swi instruc-tion.5. The software executes the rti instruc-tion.6. The software writes a 0 to the C7F bit.TFLG1 = 0x00;015 (part 1 of 1) 10 pointsOn both the 812A4 and the 9S12C32, thetimer channel 0 flag, C0F, is bit 0 of