CHEM 105 1nd Edition Lecture 3Outline of Last Lecture • The Periodic Table of the Elements • The modern periodic table contains seven horizontal rows called periods • 18 Colums called groups or families.Outline of Current Lecture • The seven diatomic elements: H2, N2, O2 , F2, Cl2 , Br2 , I2• The common forms of phosphorus and sulfur: P4 and S8• The terms group and period (in reference to the periodic table)• The four named groups• metals, nonmetals, and metalloids• The common ions formed by the elements in Figure 2.17 (page 57)Current LectureQ: Calculate the moles of titanium(IV) sulfate in 55.00g of titanium(IV) sulfateA: Ti(So4)247.87g/mol+ 2 x 32.07g/mol+ 8 x 16.00g/mol= 240.01 g/mol55.00 g Ti(So4)2 x 1 mole/240.01g = 0.229157118 mol Ti(So4)2 Q: Calculate the mass of 0.8932 mol of aluminum oxideA: Al2O32 x 26.98g/mol + 3 x 16.00g/mol= 101.96g/mol0.8932 mol Al2O3 x 101.96g/1mol =91.070672 g/mol ---> 91.07 g/mol Al2O3Q: Calculate the moles of chlorite ion in 65.37 g of strontium chloriteA: Strontium Chlorite Sr(ClO2)287.67g/mol + 2 x 35.45g/mol + 4 x 16.00g/mol= 222.54g/mol65.37g Sr(ClO2)2 x 1mol/222.52g x 2mol ClO2/ 1mol Sr(ClO2)=0.587542693g/mole ---> 0.5875 mol ClO2Balancing Chemical Equations• CH4 (g)+ 2O2 (g) ----> CO2 (g) + 2H2O (g)• 2CH3OH (I) + 3O2 (G) ----> 2CO2 (g)+ 4H2O (g)• SO2 (g) + 4HF (l) ----> SF4 (g) + 2H2O (I)• Fe2O3 (s) + 3 Mg (s) ----> 3 MgO (s0 + 2 Fe (s)• 2NaNO3 (s) + H2SO2 (aq) ----> Na2SO4 (aq) + 2HNO3 (g)• 2NaBH4 + H2SO4 (aq) ----> B2H6 +2H2 + Na2SO4 (aq) Stoichiometry“How much of the second reactant do I need to completely react with this much of the first reactant?” “How much product can be made?”mass of substance A ÷ molar mass of Amoles of substance A × mole ratio (B/A) from the balanced chemical equationmoles of substance B × molar mass (B)mass of substance
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