Section 1.12. a) negative b) negativec) positive d) positive8. a) b > 0 b) s ≤ 0c) w ≥ -4 d)15< c <13e) p ≤ -2 f) -m ≥ -2g)rs≥15 h)1f£ 14i) | x | < 412. a) 4 b)52 c) 10Section 1.24.126.5112. -12x220.-2 x6z5y24. -4x12y78.243136.4 r5654. a)4 + x x b)(4 + x) 4 + x58. -564.4 a4b78.5 x2y5286. † a2+1 ≠ a +1Section 1.36. 6x2 + 19x - 3612. 7x4 - 11x3 + 4x2 + 42x - 2418. 2a2b - 3a + b222. 25x2 - 16y238. x3 + 9x2y + 27xy2 + 27y346. 4u2 - 2uv = 2u(2u - v)54. (7x-4)(x+2)62. (3x + 4)268. (9r + 4t)(9r - 4t)72 x(x + 5)(x - 5)76. 4(4x + 3y)(4x - 3y)92. (x4 +4)(x2 + 2)(x2 - 2)100. x(2x + 1)2Section 1.44.2321610.5 - rr322.5t - 6t - 326.5 x + 42 x + 334.x(3x + 5)(x - 2)(x + 2)246.-1x( x + h)50.t - 8 t +16t - 16Section 2.16. y = -11312. x = 51522. x = 31730. All Reals, x ≠ -2540. All Reals, x ≠ ±5244. No Solutions, (x ≠ -4)66.r =A - PPt70.h =S - 2lw2(w + l)Section 2.24. $57.426. 13 hr.8. Sell $10 million in bonds andborrow $40 million.10. engineer = 8.5 hours; assistant = 3.5 hours12. Use 403ml of 1% solutionand 53ml of 10% solution14. Use 40 ml of elixirand 60 ml of syrup.18. After 1:21 PM24. h = 13 ft.30. about 3 hoursSection 2.32. x = -2, 7414. x = -13, (x ≠ -2)16. a) Nob) Yes20. x = ±7426. a)d =1694 b)d = 9c) d = ±10 d) d = ±928. x = 4 ± 536.x = -56±161348.d =gmMF, since d > 050.t =-vo+ vo2+ 2gsg54. 8 in. by 16 in.56. a. 206.25 ft. b. v = 40 mi/hr60. 1.5 in. for sides and top; 3 in. for bottom62. 32 feet of fencing66. in range until 9:24 a.m.Sections 2.44. -5 + 5i18. -122.-32-52i42. -4 ± iSection 2.54. x = 15, or x = -124. x = 9 (x = 2 is extraneous)38. y = ±1630 ± 6 1352. a) x = -243 b) x = ±125c) No real solutions d) x = 9e) No real solutions56. t = TA2k262. Change in diameter ª 1.37 ft.64. r = 3 in.Section 2.62. a) 11 > 2 b) 9 > 0c)23> -56 d)-23<564. (-∞, 5]14. 0 ≤ x < 422. (-∞, 1]54. (-∞, 2.6)» (3.4, ∞)78.209≤ x ≤ 4Section 2.72.23,74È Î Í ˘ ˚ ˙ 10.-1,43È Î Í ˘ ˚ ˙ 44. 8 < t < 12Section 3.12. It forms a star6. A(0, 4), B(-4, 0), C(0, -4),D(4, 0), E(2, 2), F(-2, -2)10. a)157 b)1,12Ê Ë Á ˆ ¯ ˜ 14. a)241 b)-2,-12Ê Ë Á ˆ ¯ ˜ 22. Show that d(A, C) = d(B, C) = 5 5Section 3.24. x-int.: (-1.5, 0), y-int.: (0, -3)12. x-int.:(-4, 0), y-int.:(0, ±2)32. It is the upper half of thecircle x2 + y2 = 4 with center (0, 0) and r = 236. (x + 4)2 + (y - 1)2 = 946. (x + 1)2 + (y - 4)2 = 2050. C(5, 0), r = 766. Find the distance between the two stationsusing the Pythagorean theorem and comparethat to the sum of their signal strengths.Section 3.32.m =1514. All four lines travel through the origin. Thoselines with positive slopes go up to the rightand those lines with negative slopes to up tothe left.20. a. y = 2b. x = -422. 2x - 3y = -1430. 2x - 3y = -734.y =65x +17536. 3x - 4y = -2156. a. P = -125t + 8250b. t = 26 monthsc. The endpoints of the graph are(0, 8250) and (66, 0)60. The year 191064. a. F = -40 b. C = 160 and F = 320Section 3.46. a. - 4a + 3 b. 4a + 3c. 4a – 3 d. - 4a – 4h + 3e. - 4a - 4h + 6 f. - 410. a. † 2a2+ 3a - 7 b. † 2a2- 3a - 7c..† -2a2- 3a + 7d. † 2a2+ 4 ah + 2h2+ 3a + 3h - 7e. † 2a2+ 2 h2+ 3a + 3h - 14f. † 4a + 2h + 312. a.-5a + 2a b.12 a - 5c.2 a - 5 d.2a - 516. a. † -5, 7[ ]b. † -1, 2[ ]c. † f 1( )= -11 d. † x = -3,-1, 3,5e. † -3,-1( )» 3, 5( )24.34,2È Î Í ˆ ¯ ˜ » 2, •( )34. a.b. D = (-∞, ∞), R = [-1, ∞)c. Decreasing on (-∞, 0]Increasing on [0, ∞)46.f ( x) = -32x + 460. a. y =4x b. S = 3x + 4 +12x68. a. † L x( )= 2500 + x - 2( )2 b. approx. 57.9 feet5]Section 3.52. Even 4. Odd 8. Neither12. Given: g(x) = | x | and f(x) = | x - c |To find f(x):For c = -3, shift g(x) left 3 unitsFor c = 1, shift g(x) right 1 unitFor c = 3, shift g(x) right 3 units14. Given: g(x) = 2x2 and f(x) = 2x2 - cto find f(x):For c = -4, shift g(x) up 4 unitsFor c = 2, shift g(x) down 2 unitsFor c = 4, shift g(x) down 4 units30. (-1, -8)36. graph of f horizontally stretched by 2 and shifted down 340. Given f(x) as drawn:a. shift f right 2 unitsb. shift f left 2 unitsc. shift f down 2 unitsd. shift f up 2 unitse. reflect f through the x-axis and verticallystretch it by a factor of 2.f. reflect f through the x-axis and verticallycompress it by a factor of 2.g. reflect f through the y-axis andhorizontally compress it by a factor of 2.h. horizontally stretch f by a factor of 2.i. reflect f about the x-axis, shift it left 4units and down 2 units.j. shift f right 4 units and up 2.44. a. † y = f x - 2( )+ 2b. † y = - f x( )c. † y = - f x + 4( )+ 248.50.62. a. D = [-6, -2], R = [-5, -2]b. D = [-3, -1], R = [-10, -4]c. D = [-4, 0], R = [-5, 1]d. D = [-10, -6], R = [-11, -5]e. D = [2, 6], R = [-10, -4]f. D = [-6, -2], R = [4, 10]64. † C x( )=0.25 if x £ 10.10 + 0.15x ifx > 1Ï Ì Ô Ó Ô Section 3.610. f(x) = -4(x - 2)2 + 316. a. x = -83,32b. -26.04 is a minimum24. y = -(x - 2)2 + 426. y = 59(x + 1)2- 230. y = 764( x - 4)2- 7Section 3.72. a. -4 b. -14c. -45 d.-9510. a. 3x2 - 6x + 3 b. 3x2 - 1c. 27x4 d. x - 218. a. 27x3 + 18x2 b. 3x3 + 6x2c. -144 d. 135Section 3.86. f is not one-to-one22.f-1(x) =-3x +1x40. a. The graphs intersect on the line y = xb. D = [1, 10], R = [0, 9]c. D1= [0, 9], R1 = [1, 10]Section 3.98. k = 2500312. k = 8516. a. I = kd2b. k = 2.5 x 109c. 89.7 candlepower24. a.V = knTP=knTPb. V is doubled.80. a. V = 6000t + 89000 …