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GOSSMONT CHEM 141 - Analysis of a 2-component Alloy

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Analysis of a 2-component AlloyProblemExperimental Set-upSlide 4Slide 5After reaction completeSlide 7Determine the pressure of the gas in the bottleSlide 9Slide 10Slide 11Now we need to account for water vapor in the gasSlide 13Now we need the volume of gasSlide 15Find two relationships involving amount of Mg and ScDefine two variables that will complete both equationsAnalysis of a 2-component AlloyExperiment 10Problem•Determine the percent zinc in an alloy•Use information regarding the amount of hydrogen gas producedExperimental Set-upreaction vessel contains HCl and alloy•Fill Bottle with water and get a mass of the full bottle. •Add 50-75 mL of dilute (6M) HCl to reaction flask and set up as in previous slide. •Secure all connections and add a weighed piece of alloy.Mass of Bottle full of water – 4.04 kgMass alloy 1.697gAfter reaction complete•Allow system to equilibrate for about 10 minutes•Clamp the tube between the bottle and the beaker•Measure the height of the water in both the bottle and the beaker•Uncork the bottle and take the temperature of the gas and the waterMass of Bottle full of water – 4.04 kgMass alloy 1.697gTemperature water – 15 oCTemperature gas – 18oCHeight of water in bottle 10.2 cmHeight of water in beaker 16.6 cmDetermine the pressure of the gas in the bottlereaction vessel contains HCl and alloyIf the level of the water in the bottle is higher than the level of the water in the beakerPgas + Pwater column = PatmosphereHeight of water columnDetermine the pressure of the gas in the bottlereaction vessel contains HCl and alloyIf the level of the water in the beaker is higher than the level of the water in the bottlePgas = Patmosphere + Pwater column Height of water columnDetermine the pressure of the gas in the bottlereaction vessel contains HCl and alloySo for our dataheight of water column = Height of water in beaker – height of water in bottle 16.6cm – 10.2cm = 6.4cm = 64mm of waterSince mercury is 13.6 times more dense than water, a 13.6 mm column of water exerts the same pressure as a 1 mm column of mercury.So a 64 mm column of water is equivalent to Height of water column = 64 mmHg 7.4 water 13.6Hg 1 water64 mmmmmmmm Determine the pressure of the gas in the bottlereaction vessel contains HCl and alloySo continuingPwater column = 4.7 torr and Patmosphere = 751.4 torr (from the barometer)And Pgas = Patmosphere + Pwater column So Pgas = 751.4 torr + 4.7 torr = 756.1 torrHeight of water column = 64 mmNow we need to account for water vapor in the gasWater temperature – 15oCVapor pressure of water at 15oC -Now we need to account for water vapor in the gasPressure of H2 gas = Pressure of gas – vapor pressure of water= 756.1 torr – 12.8 torr= 743.3 torrNow we need the volume of gasMass of Bottle full of water – 4.04 kgMass of bottle after experiment – 2.64 kgMass of water displaced = 1.40 kgUse density to determine volume 1.40 L•Pressure of gas = 756 torr•Pressure of H2 = 743 torr•Volume H2 = 1.4 L•Moles of H2 = 0.0573•Mass alloy 1.697gFind two relationships involving amount of Mg and Sc•Mass of Sc + mass of Mg = total mass•Moles of H2 from Sc + Moles of H2 from Mg = total moles H2Define two variables that will complete both equations•x = mass Sc, y = mass Mg•Mass of Sc + mass of Mg = total mass•x g Sc + y g Mg = 1.697 g sample•Moles of H2 from Sc + Moles of H2 from Mg = total moles H2222H mol 0573.0Mg mol 1H mol 1Mg g 24.3Mg mol 1Mg g Sc mol 2H mol 3Sc g 44.96Sc mol 1Sc g 


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