// Class Example: Regenerative Brayton cycle with reheat & intercooling// Given:T1 = 310 // Kp1 = 100 // kPapratio = 8p2 = p1*sqrt(pratio)p3 = p2T3 = T1p4 = p3*sqrt(pratio)T5 = 1460 // Kp5 = p4p6 = p5/sqrt(pratio)p7 = p6T7 = T5p8 = p7/sqrt(pratio)eta_c = 0.75eta_t = 0.82eff_reg = 0.65// Find: a) thermal efficiency// b) back work ratio// Assumptions: i) air-standard assumptions apply// ii) no pressure drop across intercooler, combustor, reheater, regenerator// ANALYSIS:// Compressor, 1st stageh1 = h_T("Air",T1)s1 = s_Tp("Air",T1,p1)s2s = s1s2s = s_Tp("Air",T2s,p2)h2s = h_T("Air",T2s)eta_c*(h2-h1) = h2s-h1wc1 = h2-h1T2 = T_h("Air", h2)// Compressor, 2nd stage (since stages are identical, h3=h1, h4=h2, wc2=wc1)// The following eqns are only needed if stages were not identicalh3 = h_T("Air",T3)s3 = s_Tp("Air",T3,p3)s4s = s3s4s = s_Tp("Air",T4s,p4)h4s = h_T("Air",T4s)eta_c*(h4-h3) = h4s-h3wc2 = h4-h3T4 = T_h("Air", h4)// Combustorqprim = h5-hx// Turbine, 1st stageh5 = h_T("Air",T5)s5 = s_Tp("Air",T5,p5)s6s = s5s6s = s_Tp("Air",T6s,p6)h6s = h_T("Air",T6s)eta_t*(h5-h6s) = h5-h6T6 = T_h("Air", h6)wt1 = h5-h6// Reheatqrh = h7-h6// Turbine, 2nd stage (since stages are identical, h7=h5, h8=h6, wt2=wt1)// The following eqns are only needed if stages were not identicalh7 = h_T("Air",T7)s7 = s_Tp("Air",T7,p7)s8s = s7s8s = s_Tp("Air",T8s,p8)h8s = h_T("Air",T8s)eta_t*(h7-h8s) = h7-h8wt2 = h7-h8T8 = T_h("Air", h8)// Regeneratoreff_reg*(h8-h4) = hx-h4Tx = T_h("Air", hx)hx-h4 = h8-hyTy = T_h("Air", hy)// Cyclewcycle = 2*wt1 - 2*wc1qin = qprim + qrheta = wcycle/qinbwr = wc1/wt1RESULTS:T2 451.9T2s 416.7T3 310T4 451.9T4s 416.7T6 1194T6s 1135T7 1460T8 1194T8s 1135Tx 946.1Ty 724.5bwr 0.4543eta 0.3758h1 310.1h2 453.6h2s 417.7h3 310.1h4 453.6h4s 417.7h5 1586h6 1270h6s 1201h7 1586h8 1270h8s 1201hx 984.4hy 739.4p2 282.8p3 282.8p4 800p5 800p6 282.8p7 282.8p8 100qin 917.8qprim 601.8qrh 316s1 1.739s2s 1.739s3 1.44s4s 1.44s5 2.819s6s 2.819s7 3.117s8s 3.117wc1 143.6wc2 143.6wcycle 344.9wt1 316wt2