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WCU ECO 251 - ECO 251 First Hour Exam

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251y0011 10/11/00 ECO251 QBA1 Name ____KEY___________ FIRST HOUR EXAM SECTION MWF 10 11 TR 11 12:30 OCTOBER 7, 2000 Part I. Multiple Choice (10 points)1.(D7-1) The major contribution of inferential statistics is that it a. Allows us to take population information and make statements about samples. b. Gives us a description of data contained in a sample. c. Gives us a description of data contained in a population.*d. Allows us to take sample information and make statements about the population. e. None of the above.2.(S-3) Debit balances owed in a retail store are an example of a. Ordinal data. b. Nominal data. c. Interval data.*d. Ratio data. e. None of the above.3. A used automobile dealer lists cars in the following classes. A - 100,000 miles or more on the odometer, B - less than 100,000 miles on the odometer, C - Diesel. Are these three categories a. Mutually exclusive?*b. Collectively exhaustive? c. Both mutually exclusive and collectively exhaustive? d. Neither mutually exclusive or collectively exhaustive? e. Can't tell with the information given.4. (D7-9)If a distribution is skewed to the right, we can say that it is likely that*a. Mean > median > mode b. Median > mean > mode c. Mode > median > mean d. Mode > mean > median e. Mode = mean = median (Most people got this backwards - make a diagram!)5. A graph that connects points, each of which represents the frequency  fis called a a. Histogram b. Ogive*c. Frequency Polygon d. Pie chart e. None of the above251y0011 10/11/00Part II. Compute an appropriate answer, showing your work (except in a)) (15 Points maximum - if you do more than 15 points, only your right answers will be counted.):a) Fill in the following table (3) ClassfrelfF50-59.99 _ .12 __60-69.99 4 __ __70-79.99 _ __ 1280-89.99 6 __ __90-99.99 7 _ __Total 25 __Solution:ClassfrelfF50-59.99 3 .12 360-69.99 4 .16 770-79.99 5 .20 1280-89.99 6 .24 1890-99.99 7 .28 25Total 25 1.00Note that 25n.b) Assume that we have sold 1000 life insurance policies in amounts between $5200 and $9800. If this data is to be presented in eight classes, what intervals would you use? Explain your reasoning using the appropriate formula and make a table showing the class intervals you would actually use. (3)Solution: 575852009800so use 600. This is only a suggestion. Any number somewhat above 575 will work. Class From ToA 5200 5799.99 B 5800 6399.99C 6400 6999.99D 7000 7599.99E 7600 8199.99F 8200 8799.99G 8800 9399.99H 9400 9999.99c) (S-30)If a population of 1000 items with an unknown distribution has a mean of 12 and a standard deviation of 1.2, what is the approximate minimum number of items that must be (i) between 6 and 18? (ii) What is the maximum that can be above 18? (3)Solution: (i) If we use the formula xzk, we find that 52.1126 and.52.11218 According to the Chebyshef inequality, the minimum fraction of the data that must be between 5 is 25242511112k. 2524 of 1000 is 960. (ii) The answer is the opposite to the answer to (i). There are about 1000 - 960 = 40 items left over. All ofthese could be above 18.2251y0011 10/11/00d) Do c) again assuming that the distribution is unimodal and symmetric.(2)Solution: Since the Empirical Rule says that almost all points must be between 3, we would expect almost all of the 1000 points to be between 6 and 18 since these points are5, and we would be quite surprised if even one point is above 18.e) For the numbers 11.1, 13.2, 15.1 and 12.7, compute the i) Root-mean-square ii) Harmonic mean, iii) Geometric mean (2 each)Solution: Note that 1.52x. This is not used in any of the following calculations and there is no reason why you should have computed it! (i) The Root-Mean-Square.  75.6864129.16101.22824.17421.123417.121.152.131.11411222222xnxrms6875.171. So 103.136825.17112xnxrms.(ii) The Harmonic Mean. 078740.0066225.0075758.0090090.0417.1211.1512.1311.11141111xnxh 310813.041077703.0. So 8947.12077703.01111xnxh.(iii) The Geometric Mean.       411404.280981404.280987.121.5`12.131.11441321nnngxxxxxx  25.01404.280989470.12. Or              54160.271469.258022.240695.2417.12ln1.15ln2.13ln1.11ln41)ln(1ln xnxg 56086.224346.1041. So 9470.1256086.2exg. I got the last result by putting 2.56086 into the calculator and pressing 'inverse' and then 'ln x.' Or   )log(1log xnxg         7.12log1.15log2.13log1.11log41   11217.144868.44110380.117898.112057.104532.141. So9470.121011217.1gx. I got the last result by putting 1.11217 into the calculator and pressing 'inverse' and then 'log x.'Notice that the original numbers and all the means are between 11.1 and 15.1. In spite of everything that I said, there are many of you who think that: (i) You can find a sum of squares by summing numbers and squaring the sum; (ii) You can find the sum of x1 by adding up the numbers and taking the reciprocal; (iii) You can find an nth by dividing by n. I can only recommend a remedial math class (unless, of course, you want to try listening in class and checking out the homework very carefully.)3251y0011 10/11/00Part III. Do the following problems (25 Points) 1. In a period of 7 days you make the following numbers of sales(in millions):Day : 1 2 3 4 5 6 7 Sales: 9.2 10.2 9.2 11.2 19.5 12.2 13.2 Compute the following (assuming that the numbers are a sample):a) Mean Sales (1)b) The Median (1)c) The Standard Deviation (3)d) The 2nd Quintile (2)Solution: Compute the Following: Index x 2x xx   2xx  Note that x is in order 1 9.2 84.64 -2.9 8.41 2 9.2 84.64 –2.9 8.41 3 10.2 104.04 –1.9 3.61 4 11.2 125.44 or -0.9 0.81 5 12.2 148.84 0.1 0.01


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WCU ECO 251 - ECO 251 First Hour Exam

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