DOC PREVIEW
MSU AST 207 - Hwk02Ans

This preview shows page 1 out of 2 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

AST 207 Homework 2 Due 17 September 2010 1 of 2 1. Motion of the Brightest Stars. (10 pts.) The16 brightest stars that are visible from the northern hemisphere are Sirius, Arcturus, Vega, Capella, Procyon, Rigel, Betelgeuse, Altair, Aldebaran, Spica, Antares, Pollux, Fomalhaut, Deneb, Regulus, and Castor. Choose one of them, and find (1) (1 pt.) the coordinates of the star, (2) (2 pts.) the date on which it is visible on the meridian at sunset, and (3) (2 pts.) the date on which it is rising at sunset. The meridian is the great circle line that passes through the celestial pole and the zenith. Give the declination in degrees and the right ascension in hours and minutes. (4 pts.) Explain how you found the dates. For simplicity, assume that you are on the equator. (When only one month is listed, it can be late the month before or early the month after, this range is due to varying definitions of sunset and the inaccuracy of using the celestial sphere to measure.) Star Part 1 Part 2 Part 3 Sirius 6h 45min, -17 deg April January Arcturus 14h 15min, 20 deg July April Vega 18h, 40min, 39 deg October July Capella 5h 10min, 47 deg March December Procyon 7h 35min, 6 deg April January Rigel 5h 10min, -8 deg March December Betelgeuse 5h 55min, 8 deg March-April December-January Altair 19h 50min, 6 deg October-November July-August Aldebaran 4h 35min, 16 deg Febuary-March November-December Spica 13h 25min, -11 deg June March Antares 16h 30min, -26 deg August-September May-June Pollux 7h 45min, 28 deg April January Fomalhaut 22h 57min, -29 deg December September Deneb 20h 41min, 45 deg October-November July-August Regulus 10h 8min, 12 deg May-June February-March Castor 7h 34min, 32 deg April January For question 2, put the star on the meridian by turning earth. I assume you are in Michigan. Then move the sun until it is setting, which is toward California. Then read the date next to the sun. Alternatively, you can calculate. If the star is on the meridian at sunset, the star is 6h ahead of the sun. That makes the sun’s position R.A. of the star - 6h. The sun is at zero right ascension on Mar. 21. So, convert the sun’s position from R.A. into time and add it to Mar. 21 to find the date. For (3) you do basically the same thing, but now subtract 12h from the stars position. So your answer will be very close to 3 months before your answer to (2) 2. The coordinates of the center of the Milky Way galaxy are 17hr39min right ascension and –29° declination. a. (5 pts.) When is the best time of year to observe it? Explain how you can figure this out from knowing that the right ascension of the sun is 0hr0min on the vernal equinox. You want to observe for the longest part of the night, which means it rises at sunset and sets at sunrise. In the figure, left is 0hr. Therefore the galactic center (18hr) is up. On 6/21, the sun is setting when 18hr is rising. b. (2 pts.) Is it better to observe it from Michigan or from Chile in South America? Explain your reasoning.AST 207 Homework 2 Due 17 September 2010 2 of 2 It is better to observe in Chile. Because the declination is –29°, it passes overhead at latitude –29°, which is in Chile. In Michigan, at +44° latitude, it is at best only 17° above the horizon. 3. A mental model of the sky, which we introduced in class. a. (5 pts.) A star rises at 8 pm. When does it rise two months from now? Explain how you deduced the answer. Today is close to 9/21. The arrow on the figure is you at 8pm, and the line is the horizon. (Note that because the constellations are many, many times as far from us as the sun, that to see what is somewhere in relation to the earth you have to shrink the earth’s orbit essentially down to where the sun is.) The horizon turns counterclockwise with the earth. Therefore Aries is rising. The dashed line is the horizon at noon on 11/21. (Aquarius is rising at noon.) Two hours later, Pisces is rising, and at 4pm, Aries is rising. (Every two hours, a new constellation of the zodiac is rising.) Alternatively, you can reason this way: 2 months = 4 hours of right ascension. As time goes by, stars rise earlier. Therefore it will rise 4 hours sooner at 4pm. b. (5 pts.) Which constellation of the Zodiac is high in the sky at sunset tonight? Explain how you deduced the answer. Today is nearest to 9/21. Draw the horizon, which runs from Pisces to Virgo. The sun is on the horizon. The upper half of the sky is visible. A little later, the horizon turns counterclockwise and the sun goes below the horizon. Therefore Sagittarius will be highest at sunrise. (Note that if you said your sunset was at 8pm, then Cap would be high in the


View Full Document

MSU AST 207 - Hwk02Ans

Download Hwk02Ans
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Hwk02Ans and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Hwk02Ans 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?