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CALVIN ENGR 311 - Example

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PowerPoint PresentationSlide 2Slide 3Slide 4Slide 5RE7.781 103REVEVEE( )IEIE2.02 103IEIc 1VE0.717VEVBEVBE0.717VBE0.7 VTln21RC 5 103RCVCC VCIc 100VEE 15VT0.025Ic 0.002VC 5VCC 15Example 1 - Beta = 100, vBE = 0.7V at iC = 1mA. Design circuit so that a current of 2mA flows through the collector and a voltage of +5V appears at the collector.MathCAD FileClick Here To Access ItPSpice FileClick Here To Access ItJAVA Script From Web BrowserClick Here To Access


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