Bridges Math 124#20 ANSWERS TO PRACTICE TEST 21(a)f'(a)=−2 a−3(a2sin(a2)+cos(a2))1(b)g'(t)=−10 t(1+25 t4)[arctan(5 t2)]21(c)W'(z)=z−2 /3(3 z8 /3ln z−13ln z+ z8 / 3−1)1(d)3ln ¿3tan(y−1)sec2(y−1)H'(y)=− y−2¿2.h →0−¿(dMdd)=AClim¿¿h →0−¿(dMdd)=−ACd2lim¿¿Since the LeftLimit ≠ RightLimit, the function M (d ) is not differentiable atd=C.3.x←1∨x>1 In interval notation, the answer is: (−∞ ,−1)∪(1, ∞).4(a) (i) −¿6/25 (ii) h(x ) is decreasing at x = 5 since h'(5)<0.4(b) (i) 146 (ii) h(x ) is concave up at x = -6 since h' '(−6)>0.4(c)−105. Proof -- See Text page 146: Derivative of ln x.6(a) (i); (iii) (b) (v) (c) (v)7(a) -1, 1.5 (b) 1.5, 7 (c) 7, 10, 11 (d) -1, 10, 11 (e) -1,
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