# BOISE STATE MATH 143 - Review Sheet for Test #1 (3 pages)

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# Review Sheet for Test #1

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## Review Sheet for Test #1

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Pages:
3
School:
Boise State University
Course:
Math 143 - COLLEGE ALGEBRA (3-0-3)(Area III).
##### COLLEGE ALGEBRA (3-0-3)(Area III). Documents
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MATH 143 Review Sheet for Test 1 9 21 05 Last update Tue Sep 20 08 09 47 MDT 2005 1 m143 fa05 handouts143 t1 143 921 review suggestions 1 tex 1 This list is not in final form Like stuff may yet be added to it 2 Test 1 is Wednesday 9 21 05 3 There will be a with calculator part of this exam So have some batteries in your calculator And bring it to the test 4 The test will cover the material of Assignments 1 15 roughly 5 Be sure you can a Add algebraic fractions using the Least Common Denominator b Derive the Quadratic Formula and be able to discuss the Discriminant c Make a sign change chart for a product of binomials d That you know the two big triangle theorems i Pythagoras s Theorem ii The Similar Triangles Theorem These both relate picture information to algebra These theorems lie at the base of all the straight line equations facts slope works because of the Similar Triangles Theorem the perpendicularity and slope criterion works because of Pythagoras The equation of a circle comes straight from the distance formula which in turn is a manifestation of Pythagoras s Theorem e Completing the Square lies at the heart of i deriving the quadratic formula ii parsing a quadratic in x and y equation to see whether it s a circle f Add algebraic fractions using the Least Common Denominator g Decode negative exponents in expressions h Decode fractional exponents in expressions MATH 143 Review Sheet for Test 1 9 21 05 i j 6 Re the absolute value inequalities on assignment 14 a x 1 3 For this one many folks offered this beginning ploy 3 x 1 3 which excites suspicion because it implies that 3 3 So don t do that Method A One can correctly say that this inequality means that x 1 lies at least 3 units from zero so i x 1 3 or x 2 OR ii x 1 6 3 or x 6 4 We can put these two solutions together into the BOB answer 4 2 Method B Here s the trick presented in class trade the given inequality in temporarily on the complementary inequality x 1 3 This complementary inequality says that the

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