Physics 260 Homework Solution 13 Chapter 27 1 PSE6 27 P 001 Q N e I t I t e N 2 PSE6 27 P 011 From equation I nqAvd we get the drift speed of electrons vd I nqA where n is the number of charge carriers per unit volume q is the charge carried by each electron and A is the cross sectional area of the aluminum wire To find n we need to first calculate the mass of each atom Aluminum has a molar mass 27 grams Therefore the mass per atom is 27g 4 49 10 23 g atom NA Then divide the density of Aluminum by mass per atom gives us n 3 PSE6 27 P 013 I 4 V R PSE6 27 P 047 To solve this problem first calculate the energy used by the fluorescent lamp and incandescent lightbulb t Then multiply these two values by the cost per unit energy to find out the total cost and take the difference 1 5 PSE6 27 P 058 The resistance of one wire is R 0 500 mi number of miles Thus the power loss due to resistive losses is I 2 R 6 PSE6 27 QQ 002 It is a scalar Explanations are given on page 857 in the textbook 7 PSE6 23 QQx 003 IA IB IC from the relation I V R 2
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