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UW-Madison PHYSICS 208 - PHYS 208 Lecture 23 Notes

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1Tues. Nov. 18, 2008 Phy208 Lect. 231Exam 3 is Tuesday Nov. 25Students w / scheduled academic conflict please stay after classTues. Nov. 18 (TODAY) to arrange alternate time.5:30-7 pm, 2103 Ch (here)Covers: all material since exam 2.Bring: CalculatorOne (double-sided) 8 1/2 x 11 note sheetExam review: Thursday, Nov. 20, in classTues. Nov. 18, 2008 Phy208 Lect. 232From Last Time…Photoelectric effectand light quantizationTues. Nov. 18, 2008 Phy208 Lect. 233Summary of Photoelectric effect Light comes in photons - particles of light h=Planck’s constant Red photon is low frequency, low energy. (Ultra)violet is high frequency, high energy. Electron in metal absorbs one photon Can escape metal if photon energy large enough Ephoton>Work function Eo Excess energy Ephoton-Eo shows up as kinetic energy! Ephoton= hf = hc /"Tues. Nov. 18, 2008 Phy208 Lect. 234Photon properties of light Photon of frequency f has energy hf Red light made of ONLY red photons The intensity of the beam can be increased byincreasing the number of photons/second. Photons/second = energy/second = power! Ephoton= hf = hc /"! h = 6.626 "10#34J $ s = 4.14 "10#15eV $ s! hc = 1240eV " nmTues. Nov. 18, 2008 Phy208 Lect. 235How many photons can you see?In a test of eye sensitivity, experimenters used 1 milli-second(0.001 s) flashes of green light. The lowest power light thatcould be seen was 4x10-14 Watt.How many green (500 nm, 2.5 eV) photons is this?A. 10 photonsB. 100 photonsC. 1,000 photonsD. 10,000 photons! 4 "10#14J /s( )0.001s( )= 4 "10#17J4 "10#17J( )1eV /1.6 "10#19J( )= 250eV250eV( )1photon /2.5eV( )= 100 photonsTues. Nov. 18, 2008 Phy208 Lect. 236Quantization of light Possible energies for green light (λ=500 nm)E=hfE=2hfE=3hfE=4hf One quantum of energy:one photon Two quanta of energytwo photons etc Think about light as aparticle rather than wave.Quantum mechanically, brightness can only bechanged in steps, with energy differences of hf.Energy2Tues. Nov. 18, 2008 Phy208 Lect. 237Thompson’s model of atom J.J. Thomson’s model of atom A volume of positive charge Electrons embedded throughoutthe volume A change from Newton’s modelof the atom as a tiny, hard,indestructible sphere This model is not correct!Tues. Nov. 18, 2008 Phy208 Lect. 238Tues. Nov. 18, 2008 Phy208 Lect. 239Resulted in new model Planetary model Based on results of thinfoil experiments Positive charge isconcentrated in thecenter of the atom,called the nucleus Electrons orbit thenucleus like planets orbitthe sunTues. Nov. 18, 2008 Phy208 Lect. 2310Difference between atoms Simplest is Hydrogen: 1 electron orbiting 1 proton Other atoms number of orbiting negative electrons same as number ofpositive protons in nucleus Different elements have different number oforbiting electrons Helium: 2 electrons Copper: 29 electrons Uranium: 92 electrons! Organized into periodic table of elementsFirst concentrate on hydrogen atomTues. Nov. 18, 2008 Phy208 Lect. 2311 Circular motion of orbiting electrons: electrons emit EM radiation at orbital frequency. Similar to radio waves emitted by acceleratingelectrons in a antenna. In an atom, emitted EM wave carries away energy Electron predicted to continually lose energy. The electron would eventually spiral into the nucleus However most atoms are stable!Planetary model and radiationTues. Nov. 18, 2008 Phy208 Lect. 2312Line spectra from atoms Atoms do emit radiation,but only at certain discrete frequencies. Emission pattern unique to different atoms Spectrum is an atomic ‘fingerprint’,used to identify atoms (e.g. in space).HydrogenMercuryWavelength (nm)3Tues. Nov. 18, 2008 Phy208 Lect. 2313The Bohr atom Retained ‘planetary’ picturewith circular orbits Only certain orbits are stable Radiation emitted only whenelectron jumps from onestable orbit to another. Here, the emitted photon hasan energy ofEinitial-EfinalStable orbitStable orbitEinitialEfinalPhotonTues. Nov. 18, 2008 Phy208 Lect. 2314Energy levels Instead of drawing orbits, just indicate energy anelectron would have if it were in that orbit.Zero energyn=1n=2n=3n=4! E1= "13.612 eV! E2= "13.622 eV! E3= "13.632 eVEnergy axisTues. Nov. 18, 2008 Phy208 Lect. 2315Hydrogen atom energiesZero energyn=1n=2n=3n=4! E1= "13.612 eV! E2= "13.622 eV! E3= "13.632 eVEnergy! En= "13.6n2 eV Quantized energy levels: Each corresponds todifferent Orbit radius Velocity Particle wavefunction Energy Each described by aquantum number nTues. Nov. 18, 2008 Phy208 Lect. 2316Emitting and absorbing lightPhoton is emitted when electrondrops from one quantumstate to anotherZero energyn=1n=2n=3n=4! E1= "13.612 eV! E2= "13.622 eV! E3= "13.632 eVn=1n=2n=3n=4! E1= "13.612 eV! E2= "13.622 eV! E3= "13.632 eVAbsorbing a photon of correctenergy makes electron jumpto higher quantum state.Photonabsorbed hf=E2-E1Photonemittedhf=E2-E1Tues. Nov. 18, 2008 Phy208 Lect. 2317Hydrogen emission This says hydrogen emits onlyphotons of a particular wavelength, frequency Photon energy = hf,so this means a particular energy. Conservation of energy: Energy carried away by photon is lost by the orbitingelectron.Tues. Nov. 18, 2008 Phy208 Lect. 2318Hydrogen atomAn electron drops from an -1.5 eV energy level to one withenergy of -3.4 eV. What is the wavelength of the photonemitted?A. 827 nmB. 653 nmC. 476 nmD. 365 nmE. 243 nmZero energyn=1n=2n=3n=4! E1= "13.6 eV! E2= "3.4 eV! E3= "1.5 eVPhotonemittedhf=E2-E1hf = hc/λ = 1240 eV-nm/ λ4Tues. Nov. 18, 2008 Phy208 Lect. 2319 Each orbit has a specific energyEn=-13.6/n2 Photon emitted when electronjumps from high energy to lowenergy orbit.Ei – Ef = h f Photon absorption induceselectron jump fromlow to high energy orbit.Ef – Ei = h f Agrees with experiment!Energy conservation for Bohr atomTues. Nov. 18, 2008 Phy208 Lect. 2320Hydrogen emission spectrum Hydrogen is simplest atom One electron orbiting around oneproton. The Balmer Series of emissionlines given empiricallyn = 3, λ = 656.3 nmHydrogenn = 4, λ = 486.1 nmn=3n=4! 1"m= RH122#1n2$ % & ' ( ) RH=0.01097nm-1Tues. Nov. 18, 2008 Phy208 Lect. 2321Balmer series Transitions terminate at n=2 Each energy level has energyEn=-13.6 / n2 eV E.g. n to 2 transition Emitted photon has energy Emitted wavelength! Ephoton= "13.6eVn2# $ % & ' ( " "13.6eV22# $ % & ' (


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UW-Madison PHYSICS 208 - PHYS 208 Lecture 23 Notes

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