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UNT DSCI 3710 - DSCI 3710

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Instructions:A. p > 0.10B. 0.05 < p < .10*C. 0.025 < p < .05D. .01 < p < .025E. p < .01A. p > 0.10B. 0.05 < p < .10C. 0.025 < p < .05D. .01 < p < .025E. p < .01*A. p > 0.10*B. 0.05 < p < .10C. 0.025 < p < .05D. .01 < p < .025E. p < .01A. p > 0.10*B. 0.05 < p < .10C. 0.025 < p < .05D. .01 < p < .025E. p < .01A. 99.6*B. 6.099C. 0.859D. 7.36E. 17.48A. The independent variables do not explain MPG.B. The dependent variables do not explain MPG.C. The group of independent variables has the same coefficients.D. Inconclusive since the group of variables appears to be homogeneous.E. The group of independent variables explain MPG. *B. The sedan is expected to yield 32.03 MPG and the SUV 21.39 MPG.C. Both are expected to yield 30.08 miles per gallon of gas.D. The gas mileage of the SUV is expected to be higher by 2.48 MPG.E. The gas mileage of the SUV is expected to be lower by 2.48 MPG.*A. There is no way to tell based on this output.B. 85.05%C. 92.69%D. 99.63%E. 85.91% *A. 30.08B. 15.21C. 28.54 *D. 31.02E. 37.83A. 40.739B. 47C. 31.465*D. 31.796E. 47.790A.0.01 < p-value < 0.025B. 0.005< p-value < 0.01C. p-value < .005 *D. 0.025 < p-value < 0.05E. p-value > 0.05COURSE: DSCI 3710 Print Name:Final Exam: Version A Signature:SEMESTER: Fall 2009 Student ID #:Note: Whenever question(s) are connected you may be asked to assume a result (given a value) from the previous question but this result may or may not be correct. This is to prevent you from losing points on a second question because you made a mistake on a previous question.Instructions:Please print your name and student ID number on this exam. Also, put your signature on this exam.On your scantron PRINT your name, your version, and your section number. To better protect your privacy also print your name on the backside of your scantron.You have 105 minutes to complete this exam. The exam is open book, open notes, and open mind. You may use any type of calculator but please show all your work on the exam and mark all answers on the scantron.Many of the questions follow the format of those in Hawkes Learning Systems Business Statistics (HLS). The remaining questions are either based on the Excel assignment or use an HLSBS -like approach with problems nearly identical to thoseassigned in the textbook. When you have completed the exam, please insert your scantron into the exam booklet and turn them in to your instructor.No cheating.Good luck and we wish you well on the exam.1Use the following information to answer the next six questions@pizza express boasts of an average delivery time of less than15 minutes on the orders placed from within a three mile distance from the facility. An investor doubts the claim and wants to see if the data refutes @pizza’s claim and shows they take more than 15 minutes. The investor has independent observers obtain a random sample of orders and conduct the appropriate t-test using the KPK macro at 10% significance level. The results are given below: Data t Test for Population Mean13 15Number of Observations 14 14Sample Standard Deviation 2.218801 17Sample Mean 16.000000 19Ho: xxxx Ha: xxxx 13T* 1.686342 15P[T  T*] 0.057783 14T Critical,  = 0.1 XXXX 2090% CI for Pop. Mean 14.949837 to 17.050163...17151. What is the null and alternative hypothesis for this test?A. Ho:  < 15 Ha:  > 15*  B. Ho:  ≥ 15 Ha:  < 15 C. Ho:  < 16 Ha:  ≥16D. Ho:  =15 Ha:   15E. Ho:  ≥ 16 Ha:  < 16 2. The test is based on the assumption that:A. The sample times are largeB. The sample mean is normally distributedC. The true mean is 15.4 minutes D. The sample is normally distributedE. The delivery times are normally distributed *.23. What is the best range to describe the p value (observed level of significance) of the test statistic?A. p > 0.10B. 0.05 < p < .10* C. 0.025 < p < .05D. .01 < p < .025 E. p < .014. Suppose the calculated test statistic is 4.50. What would be the p-value?A. p > 0.10B. 0.05 < p < .10 C. 0.025 < p < .05D. .01 < p < .025 E. p < .01*5. Where is the relevant “Reject Ho – region”?A. To the left of t = -1.35B. To the right of Z = 1.23C. To the left of Z = -1.23D. To the right of t = 0E. To the right of t = 1.35 *6. Assuming the calculated value of the test statistic is 1.00, what are the decision and conclusion of the test?A. Reject the null hypothesis, conclude @pizza’s claim may be justified B. Fail to reject the null hypothesis, conclude @pizza’s claim may be justified *C. Fail to reject the null hypothesis, conclude @pizza’s claim is not justifiedD. Reject the null hypothesis, conclude @pizza’s claim is not justified E. Test for @pizza’s claim is inconclusive.Use the following information to answer the next five questionsThe manager of Hybrid Motors wishes to determine if the true mean productivity of employees at its Detroit plant is any different from that at its Mexico City plant (by measuring the number of cars that one employee is involved in the of assembly per day). Random samples of employees in Detroit and Mexico City are selected, and the productivity scores at each assembly plant are recorded. The following results are obtained using alpha = 0.05 and the Excel macro. 3Detroit Mexicot-Test: Two-Sample Assuming Equal Variances457.3 56.547.8 64.3 Detroit Mexico63 .Mean 55.925 56.3285755.7 .Variance 24.045 20.85238. 49Observations 8 7. 58.2Pooled Variance 22.57148. 56Hypothesized Mean Difference 054.1df 13t Stat -0.16413P(T<=t) one-tail 0.436076t Critical one-tail XXXP(T<=t) two-tail 0.872153t Critical two-tail XXX 7. The critical value of the appropriate test statistic to conduct the test of hypothesis for the belief that there is a difference in the mean productivity is:A. -0.16B. 1.96C. 1.77D. 2.16*E. 1.6458. The calculated value of the appropriate test statistic to conduct the test of hypothesis for the belief that there is a difference in the mean productivity is:A. -0.16*B. 1.96C. 1.77D. 2.16E. 1.6459. Which of the following ranges best describes the p-value for the test statistic to conduct the test of hypothesis for the belief that there is a difference in the mean productivity?A. p > 0.10*B. 0.05 < p < .10 C. 0.025 < p < .05D. .01 < p < .025 E. p < .0110. What is the conclusion for this test?5A. Conclude there is insufficient evidence of a difference in the means because the p value is less than the level of significance. B. Conclude there is


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