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ISU CHEM 178 - CHEM_178__1-10__Kingston_elboal_CHEM_178_SI_1.22_ANWERS

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CHEM 178 SILeader: BethTuesday 1/22/08Reaction Rates1. 4NO2 (g) + O2 (g)  2N2O5 (g)a) Write the Rates for NO2, O2, and N2O5.Rate = tNO4][2tO ][2tON2][22b) If 0.024 moles of O2 are consumed in the reaction, how many moles of NO2 areconsumed? How many moles of N2O5 are created?0.024 mol O2 x 2214molOmolNO= 0.096 mol NO20.024 mol O2 x 25212molOOmolN= 0.048 mol N2O52. The initial concentration of SO2 and O2 is 0.05 M. 5 seconds into the reaction, there are 0.025 moles/L of SO3.a) Write the balanced chemical equation for the reaction.2 SO2 + O2  2 SO3 b) Write the reactions rate expressions for each product and reactant.Rate = tSO2][2tO ][2tSO2][3c) What is the average reaction rate for SO3? sec50.0025.0 MM = 0.005M/secd) What are the concentrations of SO2 and O2 after 5 seconds?sec)5(2)][]([22 initialfinalSOSOsec)5(2][][33 ifSOSO [SO2]final = ifSOSO ][][33 + [SO2]initial = -0.025M + 0.05M = 0.025Msec)5()][]([22 initialfinalOOsec)5(2][][33 ifSOSO [O2]final = (ifSOSO ][][33)/2 + [O2]initial = -.0025M/2 + 0.05M =0.0375M e) How long will it take for all of the O2 to be consumed?Δt = RateOOinitialfinal)][]([22= 0.05/0.0025= 20


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